1. 4. reason: ON bisects reason: C is the midpoint of BD. answer: answer: PO Q o a B C D R E. 2.

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Chapter2: Second-order Linear Odes
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Question
1 A A 23% 4:39 AM
B. Paragraph Proof
A
Example 3
Given: LCDB LABD; LCBD LADB
Prove: ADCB ABAD
B
Proof:
Since the given states that ZCDB LABD and 2CBD LADB; and DB = BD by Reflexive
Property of Congruence, therefore ADCB ABAD by ASA Congruence Postulate.
Example 4
Given: AHOT and A MET; T is a midpoint of HM;
20 and LE are right angles
T.
E
Prove: ΔΗΟΤ ΔΜΕΤ
Proof:
M
Statements
Reasons
1. ΔΗΟΤ αnd ΔΜΕΤ;
T is a midpoint of HM;
20 and LE are right angles
2. 20 LE (A)
3. LHTOandzMTE are vertical angles
4. ZHTO LMTE (A)
5. HT MT (S)
6. . ΔΗΟΤ ΔΜEΤ
1. Given
2. All right angles are congruent
3. Definition of angle bisector
4. Definition of midpoint
5. Definition of midpoint
6. AAS Congruence Theorem
Let's Practice!
Activity 1: Write corresponding congruent parts of two triangles using the given reason.
1.
reason: ON bisects PQ.
reason: C is the midpoint of BD.
answer:
answer:
B
PO Q
C
2.
F
R
5.
reason: EH intersects GF at I.
answer:
3.
reason: MK bisects 2JML
reason: SU is the perpendicular
bisector of RT.
K.
answer:
answer:
M.
ANALIZA A. REYES
MATH 8 QUARTER 3 WEEK 6
Page S|9
Transcribed Image Text:1 A A 23% 4:39 AM B. Paragraph Proof A Example 3 Given: LCDB LABD; LCBD LADB Prove: ADCB ABAD B Proof: Since the given states that ZCDB LABD and 2CBD LADB; and DB = BD by Reflexive Property of Congruence, therefore ADCB ABAD by ASA Congruence Postulate. Example 4 Given: AHOT and A MET; T is a midpoint of HM; 20 and LE are right angles T. E Prove: ΔΗΟΤ ΔΜΕΤ Proof: M Statements Reasons 1. ΔΗΟΤ αnd ΔΜΕΤ; T is a midpoint of HM; 20 and LE are right angles 2. 20 LE (A) 3. LHTOandzMTE are vertical angles 4. ZHTO LMTE (A) 5. HT MT (S) 6. . ΔΗΟΤ ΔΜEΤ 1. Given 2. All right angles are congruent 3. Definition of angle bisector 4. Definition of midpoint 5. Definition of midpoint 6. AAS Congruence Theorem Let's Practice! Activity 1: Write corresponding congruent parts of two triangles using the given reason. 1. reason: ON bisects PQ. reason: C is the midpoint of BD. answer: answer: B PO Q C 2. F R 5. reason: EH intersects GF at I. answer: 3. reason: MK bisects 2JML reason: SU is the perpendicular bisector of RT. K. answer: answer: M. ANALIZA A. REYES MATH 8 QUARTER 3 WEEK 6 Page S|9
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