1. (3sin y – 5x)dx+2x² cot ydy = 0 -

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 22CR
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Bernoullis miscellaneous substitution
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Exercise
Solve:
1. (3 sin y – 5x)dx+2x² cot ydy = 0
%3D
2. (x² + y²)(xdy+ydx) – xy(xdx + ydy)=0
33°C
Transcribed Image Text:Page > of 10 10 Exercise Solve: 1. (3 sin y – 5x)dx+2x² cot ydy = 0 %3D 2. (x² + y²)(xdy+ydx) – xy(xdx + ydy)=0 33°C
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