Answered: 1. 2. 3. 4. 5. 6. 7. A. Let Z be a…

1. 2. 3. 4. 5. 6. 7. A. Let Z be a standard normal variable. Find the following probabilities: P(Z < -1.96) = P(Z > 1.23 ) = P(Z >-0.15) = P(-1.34

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Hello! Please help me with this one. Please show your complete solution in a paper. Thank you!

This is a Normal Distribution also please write your answer in 4 significant figures.

1.
2.
3.
4.
5.
6.
7.
A.
Let Z be a standard normal variable. Find the
following probabilities:
P(Z < -1.96 ) =
P(Z > 1.23 ) =
P(Z >-0.15) =
P(-1.34 <Z<0.00) =
B.
B. Given a normal distribution with μ = 82 and ²=
25, find the probability that X assumes a value
less than 78 =
more than 90 =
between 75 and 80 =
Answer

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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