1) y"+y = cos y(0) = y'(0) = 2 Ꮖ .

Q: dy 30. dx x + xy² 4y y(1) = 0

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Q: Solve the initial value problems.

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Q: t(t-1)dx t(t-1) = x(x + 1), x(2) = 2 dt

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Q: y" – 6y' + 13y = 0, y(3) = 5y'(1) =9

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Q: 1.lf each exterior angle measures 10°, how many sides does this polygon have? 2. What is the measure…

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Q: y"(x) – 3y/ (x) – 4y(x) = 3e2" , y(0) = 1, y (0) = 0. | %3D

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Q: (iii) y" – y = (x+1)², y(0) = 1, y'(0) = 1. %3D %3D

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Q: Exercise 3. Solve the following initial value problems. (1) (cos t)y' + (sin t)y = 1, and y(0) = 5;…

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Q: y" + 4y = 4 sin(2x)+ 8 cos(2x), y(0) = 0, y' (0) = 1.

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Q: y" – 2y' + 2y = 0, y(0) = -2, y'(0) = 1 %3D

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Q: (a) x² y' = x; x(0) = 1, y(0) = 1. -Y₂

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Q: c) y" + 2y" = 32e²ª + 24x, y(0) = 6, y'(0) = 0, y" (0) = 14

A: As per our guideline, we are supposed to solve only first question. Kindly repost other questions as…

Q: (In a + 12x y cos a + x*y cos x)dx + (8xy cos x + 2x"y sin x)dy = 0, 4 2 y(T) = 1/27 b. y da - a(a?…

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Q: Solve the following initial value problems and solve t →& while how Describe how it will behave.

A: The objective of the question is to solve the given second order homogeneous differential equation…

Q: Question

A: We solve (a) Cauchy-Euler equation and (b) by method of undetermined coefficient.

Q: dx dt dy dt x(0) = -1, y(0) = 1 -y + 3e-t 2х + Зу I|||

A: The solution is given as

Q: Use the method of Laplace transforms to solve the given initial value problem. Here, x' and y'…

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Q: 3. As in the previous problem, consider the initial value problem dy dt = 2y √(1- 100), with y(0) =…

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Q: (v) y" – y = sech(x), y(0) = 0, y'(0) = 0. NOTE: sech(x) is the hyperbolic secant of x. In (v), it…

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Q: Water Temperature If the variance of the water temperature in a lake is 28°, how many days should…

A: Given Margin of error=moe=3, level of significance ɑ=0.05  Population variance σ 2=28

Q: dy (a) dx JE, y(1) = 2 dy (b) dt sin t + 1, y () =; dy (c) dx x +1 y(1) = 0

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Q: Consider the initial value problem y +y=1- (0) = 4 y(0) = yo-

A: We have to solve given initial value problem:

Q: (4xy + 3x²) dx + (2y + 2x²) = 0, y(0) = -2

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