1 y = 3 4x 1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I need help with this! This focuses on finding arc length. a=1 b=2 in the graphic 1
y> 0
1
11. y =
3
1<x< 2
4x
Transcribed Image Text:y> 0 1 11. y = 3 1<x< 2 4x
Expert Solution
Step 1

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.

y=\frac{1}{3}x^3+\frac{1}{4x}

take derivative

y'= \frac{d}{dx}\left(\frac{1}{3}x^3+\frac{1}{4x}\right) 

y'= \frac{d}{dx}\left(\frac{x^3}{3}\right)+\frac{d}{dx}\left(\frac{1}{4x}\right)

y'= x^2-\frac{1}{4x^2}

the given interval is 

1\leq x\leq 2

so the lower and upper limits are

a=1, b=2

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