1 +x² √x (+/- + x² Given f(x)=x√x + x and g(x) - = f(x) (exe-1-x-3/4+) (² + x² g(x) √x)² 1 ° = [e [√f(x)] [₂²¹ 2+ ]* exe-1 1 1 1 [f(x) + g(x)]' = exe-1 - -x +7- + 2x 4 x² 24/7 [f(x)g(x)]' (exe-1-a+7)(-x -2 +22 − c ) + (c - và tra) là t 1 √, which of the following is/are TRUE? -2 (x) +2x-x)(x - √x + x) (x) -
1 +x² √x (+/- + x² Given f(x)=x√x + x and g(x) - = f(x) (exe-1-x-3/4+) (² + x² g(x) √x)² 1 ° = [e [√f(x)] [₂²¹ 2+ ]* exe-1 1 1 1 [f(x) + g(x)]' = exe-1 - -x +7- + 2x 4 x² 24/7 [f(x)g(x)]' (exe-1-a+7)(-x -2 +22 − c ) + (c - và tra) là t 1 √, which of the following is/are TRUE? -2 (x) +2x-x)(x - √x + x) (x) -
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
100%
4.4 Please answer ASAP
![1
Given f(x)
xe
+ x²-√, which of the following is/are TRUE?
X
0
(exe-1 x
-2
+π) (²/²/2+x²
(x) + 2x − x)(x²-√√x + πx)
-
=
g(x)
(=/3 + x²
√x) ²
0
¯ [√f(x)]' = 1/2 [еx²-¹ - ¼ x²
-1
exe
+ T
[f(x) + g(x)]'
= exe-1
-
- 1/2 ² ² + x - 12/23 +22-23/1/201
x
2x
4
x²
2√3
○ [f(x)g(x)]' = (ex²-¹ —_ ½ x ² + π)(-x² + 2x − ²½ x¯¹7) + (x² − √x+x)( ½ + x² .
=
√x + x and g(x)
-3/4
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec441617-bb11-49c8-90e3-e7073e779491%2F7aa8743e-8b5e-4014-af92-fa5fd330fcd8%2F3tf950s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1
Given f(x)
xe
+ x²-√, which of the following is/are TRUE?
X
0
(exe-1 x
-2
+π) (²/²/2+x²
(x) + 2x − x)(x²-√√x + πx)
-
=
g(x)
(=/3 + x²
√x) ²
0
¯ [√f(x)]' = 1/2 [еx²-¹ - ¼ x²
-1
exe
+ T
[f(x) + g(x)]'
= exe-1
-
- 1/2 ² ² + x - 12/23 +22-23/1/201
x
2x
4
x²
2√3
○ [f(x)g(x)]' = (ex²-¹ —_ ½ x ² + π)(-x² + 2x − ²½ x¯¹7) + (x² − √x+x)( ½ + x² .
=
√x + x and g(x)
-3/4
=
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