1 (x + 1)2 dx -2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine if the given is divergent or convergent using the theorem.

MUST REMEMBER! For integrals of functions with infinite discontinuity over bounded
intervals:
Theorem 3.11. Assume that f is continuous on the indicated interval.
1. On (a, b], with lim f(x) = ±0, we have
f(x) dx = lim| f(x) dx .
t-a
2. On [a, b), with lim f(x) = ±∞, we have
f(x) dx = lim
s-b
f(x) dx .
3. On [a, b], except at ce (a, b) with lim|f(x)| = +∞, we have
f(x
f(x)
= lim f(x) dx + lim f(x) dx.
provided these limits exist (i.e. finite number). The improper integral is said to be convergent if the
corresponding limit exists. Else, it is divergent.
Transcribed Image Text:MUST REMEMBER! For integrals of functions with infinite discontinuity over bounded intervals: Theorem 3.11. Assume that f is continuous on the indicated interval. 1. On (a, b], with lim f(x) = ±0, we have f(x) dx = lim| f(x) dx . t-a 2. On [a, b), with lim f(x) = ±∞, we have f(x) dx = lim s-b f(x) dx . 3. On [a, b], except at ce (a, b) with lim|f(x)| = +∞, we have f(x f(x) = lim f(x) dx + lim f(x) dx. provided these limits exist (i.e. finite number). The improper integral is said to be convergent if the corresponding limit exists. Else, it is divergent.
1
dx
(х + 1)2
-2
Transcribed Image Text:1 dx (х + 1)2 -2
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