1- Write a Java code that asks the user to enter the integer (XA, YA) Ccoordinate of a point A and the slope (a) and the slope-intercept (b) of a straight line, reads these data, and calculate the distance from this point A to the given straight line: Line equation: y = ax + b After reading the coordinates of the point and the line equation, you need to get the equation of the line that passes through A and perpendicular to the original one as follows: The slope of the perpendicular line (ap) is the negative inverse of the slope of the original line: ap = -1/a The slope-intercept (br) of the perpendicular line calculated by replacing the coordinates of point A into the equation: bp = YA - APXA Once you get the equation of the perpendicular line, you need to calculate the coordinates (x, yı) of the intersection point between the original line and the perpendicular one as follows. bp – b X1 = а — ар У 3 ах, + b Lastly, get the distance as follows: distance = J(xXA – x1)² + (Ya – yı)² When printing the slope and the slope-intercept values, DON'T ENTER THEM MANUALLY (otherwise marks will be deducted).
1- Write a Java code that asks the user to enter the integer (XA, YA) Ccoordinate of a point A and the slope (a) and the slope-intercept (b) of a straight line, reads these data, and calculate the distance from this point A to the given straight line: Line equation: y = ax + b After reading the coordinates of the point and the line equation, you need to get the equation of the line that passes through A and perpendicular to the original one as follows: The slope of the perpendicular line (ap) is the negative inverse of the slope of the original line: ap = -1/a The slope-intercept (br) of the perpendicular line calculated by replacing the coordinates of point A into the equation: bp = YA - APXA Once you get the equation of the perpendicular line, you need to calculate the coordinates (x, yı) of the intersection point between the original line and the perpendicular one as follows. bp – b X1 = а — ар У 3 ах, + b Lastly, get the distance as follows: distance = J(xXA – x1)² + (Ya – yı)² When printing the slope and the slope-intercept values, DON'T ENTER THEM MANUALLY (otherwise marks will be deducted).
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Subject: Java
Transcribed Image Text:1- Write a Java code that asks the user to enter the integer (XA, YA) coordinate of a point A and the
slope (a) and the slope-intercept (b) of a straight line, reads these data, and calculate the distance
from this point A to the given straight line:
Line equation: y = ax + b
After reading the coordinates of the point and the line equation, you need to get the equation
of the line that passes through A and perpendicular to the original one as follows:
The slope of the perpendicular line (ap) is the negative inverse of the slope of the original line:
ap = -1/a
The slope-intercept (bp) of the perpendicular line calculated by replacing the coordinates of
point A into the equation:
bp = YA - APXĄ
Once you get the equation of the perpendicular line, you need to calculate the coordinates (xı, yı)
of the intersection point between the original line and the perpendicular one as follows.
bp –
а — ар
У — ах, + b
Lastly, get the distance as follows:
distance =
V(xA – x1)² + (Ya – yı)?
When printing the slope and the slope-intercept values, DON'T ENTER THEM MANUALLY
(otherwise marks will be deducted).
The output should be as follows
Enter the x coordinate of point A: 1
Enter the y coordinate of point A: 1
Enter the slope of the line: 1
Enter the slope-intercept of the line: 10
The slope of the perpendicular line is: -1.0
The slope intercept of the perpendicular line is: 2.0
The corrdinates of the intersection point are x = -4.0 and y = 6.0
The distance from point A to the line is: 7.0710678118654755!!
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