1- When crops get disease, they produce less yield; look at the following data. Yield (kg) 8.5 8.2 7.8 Disease (%)T 11 15 17 10 25 22 30 45 51 8. 12 28 6.5 6.0. 4.6 2.2 1.0 9.3 8.3 6.9 How answer the following questions: 10.000 How many degrees of freedom are there in this correlation analysis? What is the value of r? -0.980 Is the correlation coefficient positive or negative? Positive Negative (Tick one box) Significant Not Is the correlation significant or non-significant? significant (Tick one box) P 0.05 P 0.01 P<0.001 What is the best estimate of the value of P? Tick one box)

1- When crops get disease, they produce less yield; look at the following data. Yield (kg) 8.5 8.2 7.8 Disease (%)T 11 15 17 10 25 22 30 45 51 8. 12 28 6.5 6.0. 4.6 2.2 1.0 9.3 8.3 6.9 How answer the following questions: 10.000 How many degrees of freedom are there in this correlation analysis? What is the value of r? -0.980 Is the correlation coefficient positive or negative? Positive Negative (Tick one box) Significant Not Is the correlation significant or non-significant? significant (Tick one box) P 0.05 P 0.01 P<0.001 What is the best estimate of the value of P? Tick one box)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A biologist looked at the relationship between number of seeds a plant produces and the percent of those seeds that sprout. The results of the survey are shown below. Seeds Produced 65 51 59 66 42 62 61 69 65 Sprout Percent 64.5 65.5 64.5 49 72 61 50.5 54.5 50.5 Find the correlation coefficient: r=r= Round to 3 decimal places. The null and alternative hypotheses for correlation are:H0:H0: == 0H1:H1: ≠≠ 0 The p-value is: ? (Round to 5 decimal places) r2 = ? (Round to 3 decimal places)
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A biologist looked at the relationship between number of seeds a plant produces and the percent of those seeds that sprout. The results of the survey are shown below. Seeds Produced 48 48 42 51 56 43 53 Sprout Percent 59 68 60 55.5 49 64.5 48.5 a. Find the correlation coefficient: r = Round to 2 decimal places. b. The null and alternative hypotheses for correlation are: Ho: pv H1: pv = 0 The p-value is: (Round to four decimal places) c. Use a level of significance of a = 0.05 to state the conclusion of the hypothesis test in the context of the study. O There is statistically significant evidence to conclude that a plant that produces more seeds will have seeds with a lower sprout rate than a plant that produces fewer seeds. O There is statistically insignificant evidence to conclude that there is a correlation between the number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the use of the regression line is not appropriate. O There is statistically…