1) What is the angle between the tension and displacement vectors? A) 0° B) 30° C) 45° D) 60° E) 90° F) 135° G) 180° H) 270° I) 360° 2) What is the angle between the normal force and displacement vectors? A) 0° B) 30° C) 45° D) 60° E) 90° F) 135° G) 180° H) 270° I) 360° 3) What is the angle between the weight and displacement vectors? A) 0° B) 30° C) 45° D) 60° E) 90° F) 135° G) 180° H) 270° I) 360° 4) What is the angle between the friction and displacement vectors? A) 0° B) 30° C) 45° D) 60° E) 90° F) 135° G) 180° H) 270° I) 360° 5) What is the angle between the net force and displacement vectors? A) 0° B) 30° C) 45° D) 60° E) 90° F) 135° G) 180° H) 270° I) 360° 6) Calculate the magnitude of the normal force with which the ground pushes upon the sled. A)0 N B)12.30 N C)49.05 N D)68.67 N E)111.6 N F)123.0 N G)490.5 N H)686.7 N I)1116. N 7) Calculate the magnitude of the force of friction acting on the sled. A)0 N B)12.30 N C)49.05 N D)68.67 N E)111.6 N F)123.0 N G)490.5 N H)686.7 N I)1116. N
1) What is the angle between the tension and displacement vectors?
A) 0°
B) 30°
C) 45°
D) 60°
E) 90°
F) 135°
G) 180°
H) 270°
I) 360°
2) What is the angle between the normal force and displacement vectors?
A) 0°
B) 30°
C) 45°
D) 60°
E) 90°
F) 135°
G) 180°
H) 270°
I) 360°
3) What is the angle between the weight and displacement vectors?
A) 0°
B) 30°
C) 45°
D) 60°
E) 90°
F) 135°
G) 180°
H) 270°
I) 360°
4) What is the angle between the friction and displacement vectors?
A) 0°
B) 30°
C) 45°
D) 60°
E) 90°
F) 135°
G) 180°
H) 270°
I) 360°
5) What is the angle between the net force and displacement vectors?
A) 0°
B) 30°
C) 45°
D) 60°
E) 90°
F) 135°
G) 180°
H) 270°
I) 360°
6) Calculate the magnitude of the normal force with which the ground pushes upon the sled.
A)0 N
B)12.30 N
C)49.05 N
D)68.67 N
E)111.6 N
F)123.0 N
G)490.5 N
H)686.7 N
I)1116. N
7) Calculate the magnitude of the
A)0 N
B)12.30 N
C)49.05 N
D)68.67 N
E)111.6 N
F)123.0 N
G)490.5 N
H)686.7 N
I)1116. N
![L04.01 Work Lab
All questions on this assessment use the same scenario: A team of sled dogs pull a 50.00 kg dogsled via
the tension (magnitude 85.0 N) in a horizontal cord that connects the dogs to the sled. The force of
friction between the waxed wood of the sled's skis and the wet snow acts in the direction opposite to
the sled's displacement, which has a magnitude of 15.00 m.
The FBD for the sled is given for you below, so we're all understanding the scenario the same way.
1.
EN
7x
k.
FG
10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea749dc0-32a6-4a99-ad90-a2546c610f32%2F2adeec8a-eb24-4669-aa3a-531e19c8d27f%2F0ji1dd8_processed.jpeg&w=3840&q=75)
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