Answered: 1- What are the two main criteria of…

1- What are the two main criteria of pavement failure in mechanistic-experimental design approach? Explain the type and location of applied stresses.

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter19: Design Of Flexible Highway Pavements

Section: Chapter Questions

Problem 17P

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Concept explainers

Pavement Management

Pavement management is the process of planning the maintenance and repair of a roadway network or other paved infrastructure to improve road conditions throughout the network. It is also used on runways and airports. Every highway superintendent undertakes walkway management. Traffic management includes the cost of living cycles in a systematic way of repairing minor and major roads and reconstruction projects. The needs of the entire network and budget estimates are considered before the projects are undertaken, as the cost of data collection can change significantly. Pavement management incorporates many of the features and functions required to maintain the quality of the paved material as well as to ensure that the entire road network can sustain itself at the required levels. Although pedestrian management involves the life cycle of commuting from planning to maintenance of any transport infrastructure, road asset management, and road maintenance planning is primarily aimed at road infrastructure.

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approach? Explain the type and location of applied stresses.

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Similar questions

Describe these five (5) types of pavement deformations (A-E) and then discuss the causes and propose the proper solutions of each type.
Explain with sketches, the basis of Austroads mechanistic pavement thickness design method (i.e. what theories and assumptions are these methods based on). What is the major difference between the Austroads mechanistic-empirical (CIRCLY) design method and other mechanistic-empirical design methods?
Explain the pavement using the mechanistic empirical method?
2. What are various failures in Flexible Pavement’s, explain with the help of diagrams?
Please answer pricsely
2- Describe six of the main differences between rigid and flexible pavements.
4.13) A rigid pavement is being designed with the same parameters as used in Problem 4.5. The modulus of subgrade reaction is 300 1b/in? and the slab thickness is determined to be 8.5 inches. The load transfer coefficient is 3.0, the drainage coefficient is 1.0, and the modulus of elasticity is 4 million Ib/in?. What is the design modulus of rupture? (Assume that any parameters not given in this problem are the same as those given in Problem 4.5.) 4.5 has been added for reference.
A rigid pavement is designed with a 11-inch slab, an E_c of 6 million Ib/in^2, a concrete modulus of rupture of 432 Ib/in^2, a load transfer coefficient of 3.0, an initial PSI of 4.50, and a TSI of 2.5. The overall standard deviation is 0.56, the modulus of subgrade reaction is 190 Ib/in^3, and a reliability of 90% is used along with a drainage coefficient of 0.87. The pavement is designed assuming that traffic is composed entirely of trucks (50 per day). Each truck has one 20-kip single axle and one 42-kip tandem axle (the effect of all other vehicles is ignored). A section of this road is to be replaced (due to different subgrade characteristics) with a flexible pavement having a SN of 5 and is expected to last the same number of years as the rigid pavement. What is the assumed soil resilient modulus? (Assume that all other factors are the same as for the rigid pavement). Please report your answer as a decimal in units of Ib/in^2. For example, report 3000.6 Ib/in^2 as 3000.6.
Explain the following rigid pavement distresses with the aid of sketches:i. Fatigue cracking (bottom-up) ii. Fatigue cracking (top-down) iii. Punch-out failure
What are the causes of pavement distresses, explain?
23. In the PCA design procedure of rigid highway pavements, the erosion damage analysis was devised to control the following distresses:a. Subgrade erosion, pumping and faultingb. Shattered slab and ASRc. Shrinkage cracking and joint sealant deteriorationd. None of the above
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