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1) We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following. Each card will have: i) One rank from 1 to 17. ii) One of 6 different suits. Hence, there are 102 cards in the deck with 17 ranks for each of the 6 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards! The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get. a) How many different ways are there to get any 5 card hand? The number of ways of getting any 5 card hand is b)How many different ways are there to get exactly 1 pair (i.e. 2 cards with the same rank)? The number of ways of getting exactly 1 pair is

1) We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following. Each card will have: i) One rank from 1 to 17. ii) One of 6 different suits. Hence, there are 102 cards in the deck with 17 ranks for each of the 6 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards! The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get. a) How many different ways are there to get any 5 card hand? The number of ways of getting any 5 card hand is b)How many different ways are there to get exactly 1 pair (i.e. 2 cards with the same rank)? The number of ways of getting exactly 1 pair is

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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1) We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following. Each card will have: i) One rank from 1 to 17. ii) One of 6 different suits. Hence, there are 102 cards in the deck with 17 ranks for each of the 6 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards! The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get. a) How many different ways are there to get any 5 card hand? The number of ways of getting any 5 card hand is b)How many different ways are there to get exactly 1 pair (i.e. 2 cards with the same rank)? The number of ways of getting exactly 1 pair is What is the probability of being dealt exactly 1 pair? Round your answer to 7 decimal places.
Transcribed Image Text:1) We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following. Each card will have: i) One rank from 1 to 17. ii) One of 6 different suits. Hence, there are 102 cards in the deck with 17 ranks for each of the 6 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards! The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get. a) How many different ways are there to get any 5 card hand? The number of ways of getting any 5 card hand is b)How many different ways are there to get exactly 1 pair (i.e. 2 cards with the same rank)? The number of ways of getting exactly 1 pair is What is the probability of being dealt exactly 1 pair? Round your answer to 7 decimal places.
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