1 Using u = 1 + 2x6, then the integral | x°(1+ 2x6)5 dx becomes 12 us du- This evaluates as 5+1 1 12 5 +1 12 6

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.4: Definition Of Function
Problem 51E
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Step 3
Thus the indefinite integral / x5 (1 + 2x6)5 dx becomes
12
du-
We must also convert the integral limits.
If x = 1, then u = 3
3
If x = 0, then u = 1
1
Step 4
'3
Using u = 1 + 2x°, then the integral x5(1 + 2x6)5 dx
1
becomes
12
u5 du-
This evaluates as
5+1
1
1
12
5 +1
12
Transcribed Image Text:Step 3 Thus the indefinite integral / x5 (1 + 2x6)5 dx becomes 12 du- We must also convert the integral limits. If x = 1, then u = 3 3 If x = 0, then u = 1 1 Step 4 '3 Using u = 1 + 2x°, then the integral x5(1 + 2x6)5 dx 1 becomes 12 u5 du- This evaluates as 5+1 1 1 12 5 +1 12
Tutorial Exercise
Evaluate the definite integral.
x5(1 + 2x6)5 dx
Step 1
If we let u = 1 + 2x6, then du
12x
dx.
12
Step 2
If u = 1 + 2x6 is substituted into x5 (1 + 2x6)5 dx, then we have
|
x5(1 + 2x)5 dx =
u5x5 dx.
We must also convert x dx into an expression involving u.
Using du = 12x5 dx, then we get
1
1
x5 dx =
du
np-
12
Step 3
Thus the indefinite integral
| x5 (1 + 2x6)5 dx becomes
du-
12
We must also convert the integral limits.
Transcribed Image Text:Tutorial Exercise Evaluate the definite integral. x5(1 + 2x6)5 dx Step 1 If we let u = 1 + 2x6, then du 12x dx. 12 Step 2 If u = 1 + 2x6 is substituted into x5 (1 + 2x6)5 dx, then we have | x5(1 + 2x)5 dx = u5x5 dx. We must also convert x dx into an expression involving u. Using du = 12x5 dx, then we get 1 1 x5 dx = du np- 12 Step 3 Thus the indefinite integral | x5 (1 + 2x6)5 dx becomes du- 12 We must also convert the integral limits.
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