Can someone please help? Thank you. 1) Two schools are represented by points A(2, 20) and B(14, 24) on the graph below. A roadrepresented by the line R with equation -x + y = 4, passes near the schools. An architect isasked to determine the location of a new bus stop on the road such that it is the same distancefrom the two schools.2824-20-16-12-∞BR12 16 20 24a) Find the equation of the perpendicular bisector of [AB]. Give yourequation in the form y = mx + c.b) Determine the coordinates of the point on R where the bus stopshould be located.

The product of the slopes of two perpendicular lines is -1. The distance(d) between two points: x1, y1, x2, y2 is calculated using the formula: d=x2-x12+y2-y12.The midpoint connecting the points: 2,20, 14,24 is 2+142, 20+242=8, 22. The slope of the line: connecting the points: 2,20, 14,24 is 24-2014-2=13. Hence, the slope of the perpendicular bisector is -3. The equation of the line that passes through the point: 8, 22 and has a slope of -3 can be defined as follows. y-22=-3x-8=-3x+24y=-3x+24+22=-3x+46 Hence, the equation of the perpendicular bisector is y=-3x+46.The equation of the line can be rewritten as: y=x+4. Hence, any point on the line: y=x+4 is x, x+4. Let the coordinates of R be: Rx, x+4. The distance between the points: Rx, x+4 and A2,20 is RA=x-22+x+4-202. The distance between the points: Rx, x+4 and B14,24 is RB=x-142+x+4-242. Equate these distances with each other and solve for x to obtain its value. RA=RBx-22+x+4-202=x-142+x+4-242x-22+x+4-202=x-142+x+4-242x-22+x-162=x-142+x-2022x2-36x+260=2x2-68x+59632x=336x=212=10.5 Calculate the y-coordinate as follows. y=x+4=10.5+4=14.5 Hence, the coordinates of R are 10.5, 14.5.