(1) Two bullets are fired, one 0.020 kg from a 5kg riffle, the other 0.015 kg, revolver. Which one has a bigger recoil and how much?o 28sm orl.n0A to sandal 1.004
(1) Two bullets are fired, one 0.020 kg from a 5kg riffle, the other 0.015 kg, revolver. Which one has a bigger recoil and how much?o 28sm orl.n0A to sandal 1.004
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Physics Recoil Calculation**
**Problem Statement:**
Two bullets are fired: one 0.020 kg from a 5 kg rifle, the other 0.015 kg from a 2 kg revolver. Which one has a bigger recoil and by how much?
**For the Rifle:**
Equation:
(0.020 kg × v₁) + (5 kg × V₁) = 0
\[ \text{Recoil}_1 = -5 \times 0.004 \, V_{b1} \]
\[ = -0.02 \, V_{b1} \]
**For the Revolver:**
Equation:
(0.015 kg × v₂) + (2 kg × V₂) = 0
\[ V₂ = \frac{-2}{0.015} \times V₂ \]
Here,
\[ V_R = -0.0075 \, V_{b2} \]
Calculation:
\[ V₁ = -250 \times V₁ \]
\[ V₂ = -133.33 \times V₂ \]
**Conclusion:**
The rifle bullet should have a bigger recoil.
**Additional Calculation:**
Ratio of velocities:
\[ \frac{V₁}{V₂} = \frac{5}{0.020} \times \frac{0.015}{2} \]
**Explanation:**
1. Conservation of momentum is applied for both rifle and revolver.
2. Equations relate mass and velocity to determine the recoil.
3. The negative signs indicate direction opposite to the bullet's motion.
4. A comparison is made to conclude which has a bigger recoil based on the calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25f7872c-ab16-475e-aaa5-d36f49bf1e01%2F3c7deaa4-3c50-4f69-97f7-9c31db664d39%2Fulrlfda_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Recoil Calculation**
**Problem Statement:**
Two bullets are fired: one 0.020 kg from a 5 kg rifle, the other 0.015 kg from a 2 kg revolver. Which one has a bigger recoil and by how much?
**For the Rifle:**
Equation:
(0.020 kg × v₁) + (5 kg × V₁) = 0
\[ \text{Recoil}_1 = -5 \times 0.004 \, V_{b1} \]
\[ = -0.02 \, V_{b1} \]
**For the Revolver:**
Equation:
(0.015 kg × v₂) + (2 kg × V₂) = 0
\[ V₂ = \frac{-2}{0.015} \times V₂ \]
Here,
\[ V_R = -0.0075 \, V_{b2} \]
Calculation:
\[ V₁ = -250 \times V₁ \]
\[ V₂ = -133.33 \times V₂ \]
**Conclusion:**
The rifle bullet should have a bigger recoil.
**Additional Calculation:**
Ratio of velocities:
\[ \frac{V₁}{V₂} = \frac{5}{0.020} \times \frac{0.015}{2} \]
**Explanation:**
1. Conservation of momentum is applied for both rifle and revolver.
2. Equations relate mass and velocity to determine the recoil.
3. The negative signs indicate direction opposite to the bullet's motion.
4. A comparison is made to conclude which has a bigger recoil based on the calculations.
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