1 This loudspeaker has a weight of 70 Newtons and is being held up by two cables. Both cables are at an angle of 25 degrees. This means that they both have the same tension, T. What is the vertical component of the tension in each cable? Ty = 35 unit N What is the horizontal component of the tension in each cable? Tx unit N = 75.057 What is the total tension in each cable? T = unit N %3D

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question

What is T?

## Transcription and Explanation for Educational Website

### Diagram Explanation:
The diagram shows a loudspeaker being suspended by two cables. The cables are attached to a surface and form an angle \( \theta = 25^\circ \) with the vertical. The loudspeaker is labeled with a weight (\( W \)) of 70 Newtons. Each cable carries the same tension, denoted as \( T \).

### Text Explanation:

This loudspeaker has a weight of 70 Newtons and is being held up by two cables. Both cables are at an angle of 25 degrees. This means that they both have the same tension, \( T \).

#### Questions and Answers:

1. **What is the vertical component of the tension in each cable?**

   \( T_y = 35 \, \text{N} \) 

2. **What is the horizontal component of the tension in each cable?**

   \( T_x = 75.057 \, \text{N} \)

3. **What is the total tension in each cable?**

   \( T = \) [Input required]

### Calculation Insights:
- To find the vertical component (\( T_y \)), the weight is divided equally between the two cables. Since the total weight is 70 Newtons, each cable supports 35 Newtons vertically.
- The horizontal component (\( T_x \)) is calculated using trigonometric functions, considering the angle of 25 degrees.
- The total tension (\( T \)) needs further calculation using Pythagorean identity: \( T = \sqrt{T_x^2 + T_y^2} \), taking into account both components.

This example illustrates the fundamental physics principle of tension in cables, which involves breaking down forces into their components and using trigonometry to solve for unknown quantities.
Transcribed Image Text:## Transcription and Explanation for Educational Website ### Diagram Explanation: The diagram shows a loudspeaker being suspended by two cables. The cables are attached to a surface and form an angle \( \theta = 25^\circ \) with the vertical. The loudspeaker is labeled with a weight (\( W \)) of 70 Newtons. Each cable carries the same tension, denoted as \( T \). ### Text Explanation: This loudspeaker has a weight of 70 Newtons and is being held up by two cables. Both cables are at an angle of 25 degrees. This means that they both have the same tension, \( T \). #### Questions and Answers: 1. **What is the vertical component of the tension in each cable?** \( T_y = 35 \, \text{N} \) 2. **What is the horizontal component of the tension in each cable?** \( T_x = 75.057 \, \text{N} \) 3. **What is the total tension in each cable?** \( T = \) [Input required] ### Calculation Insights: - To find the vertical component (\( T_y \)), the weight is divided equally between the two cables. Since the total weight is 70 Newtons, each cable supports 35 Newtons vertically. - The horizontal component (\( T_x \)) is calculated using trigonometric functions, considering the angle of 25 degrees. - The total tension (\( T \)) needs further calculation using Pythagorean identity: \( T = \sqrt{T_x^2 + T_y^2} \), taking into account both components. This example illustrates the fundamental physics principle of tension in cables, which involves breaking down forces into their components and using trigonometry to solve for unknown quantities.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
First law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON