1) There is no initial energy stored in this circuit i(0) = 0. Find i₁ (t) for t> 0. 8.4 H 10 H 336 V Σ • 48 Ω i₁(t)= 15-14e-2t-e-12t i₁(t) = 15+ 14e2t + e-2t Option 1 Option 2 i(t)=15-14e¯ 0 4202 Ω -2t - 12e-t
1) There is no initial energy stored in this circuit i(0) = 0. Find i₁ (t) for t> 0. 8.4 H 10 H 336 V Σ • 48 Ω i₁(t)= 15-14e-2t-e-12t i₁(t) = 15+ 14e2t + e-2t Option 1 Option 2 i(t)=15-14e¯ 0 4202 Ω -2t - 12e-t
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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Question
![1) There is no initial energy stored in this circuit i(0) = 0. Find i₁ (t) for t > 0.
8.4 H
10 H
t=0
i₁
48 Ω
i₁(t)=15+14e²t + e-2t
O Option 2
336 V
{42 Ω
i₁(t)= 1514e-2te-12t
Option 1
₁ (t) = 1514e-2t 12e-t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe98022bb-71ac-490c-af44-2a16582eafc1%2Fe0a2937e-f969-41ac-b3ab-1a4b83b8e01a%2Fdi9fb1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) There is no initial energy stored in this circuit i(0) = 0. Find i₁ (t) for t > 0.
8.4 H
10 H
t=0
i₁
48 Ω
i₁(t)=15+14e²t + e-2t
O Option 2
336 V
{42 Ω
i₁(t)= 1514e-2te-12t
Option 1
₁ (t) = 1514e-2t 12e-t
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