1) The equilibrium constant (K) of the 2A(g) + BA2(s) 2 B(s) + 2A2(g) reaction is 0.147 at 1200 K. B(s) and BA2(s) are the pure substances involved in this reaction. The partial pressures of A2(g) and A(g) in a reactor are adjusted to 0.33 and 1.2 atm, respectively at 1200 K. a) Calculate the reaction quotient (Q). b) Calculate the Gibbs free energy change (AG) for the reaction at 1200 K. c) What is the spontaneous direction of the reaction under the given conditions?

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Chapter12: Chemical Equilibrium
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1) The equilibrium constant (K) of the 2A(g) + BA2(s) 2 B(s) + 2A2(g) reaction is 0.147 at 1200 K.
B(s) and BA2(s) are the pure substances involved in this reaction. The partial pressures of A2(g) and
A(g) in a reactor are adjusted to 0.33 and 1.2 atm, respectively at 1200 K.
a) Calculate the reaction quotient (Q).
b) Calculate the Gibbs free energy change (AG) for the reaction at 1200 K.
c) What is the spontaneous direction of the reaction under the given conditions?
Transcribed Image Text:1) The equilibrium constant (K) of the 2A(g) + BA2(s) 2 B(s) + 2A2(g) reaction is 0.147 at 1200 K. B(s) and BA2(s) are the pure substances involved in this reaction. The partial pressures of A2(g) and A(g) in a reactor are adjusted to 0.33 and 1.2 atm, respectively at 1200 K. a) Calculate the reaction quotient (Q). b) Calculate the Gibbs free energy change (AG) for the reaction at 1200 K. c) What is the spontaneous direction of the reaction under the given conditions?
AG = AG° + RTINQ
AG° = –RTlnK
ai = X¡Yi
AGideal
RT (xĄlnxa + XBlnxB)
AG*S = XAuXNi
) "Lau.ni(Xau – Xni)
v=0
R = 8.314 J. mol-1. K-1 = 1.987cal.mol-1.K-1
Transcribed Image Text:AG = AG° + RTINQ AG° = –RTlnK ai = X¡Yi AGideal RT (xĄlnxa + XBlnxB) AG*S = XAuXNi ) "Lau.ni(Xau – Xni) v=0 R = 8.314 J. mol-1. K-1 = 1.987cal.mol-1.K-1
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