1- The degrees of freedom of an N-bar linkage containing only full revolute joints is ... a- M = N-3 b- M = N+3 c- M = N-1 d- M = N-2 3- The mobility of a fourbar linkage that has only 4 full revolute joint is .. • a- M = 1 b- M = 2 c- M = 0 d- M = -1 8- If a binary link is removed from a fivebar linkage containing only full revolute joints, the mobility of resulting linkage will be . -a- reduced by 1 b- increased by 1 C- reduced by 2 d- increased by 2
1- The degrees of freedom of an N-bar linkage containing only full revolute joints is ... a- M = N-3 b- M = N+3 c- M = N-1 d- M = N-2 3- The mobility of a fourbar linkage that has only 4 full revolute joint is .. • a- M = 1 b- M = 2 c- M = 0 d- M = -1 8- If a binary link is removed from a fivebar linkage containing only full revolute joints, the mobility of resulting linkage will be . -a- reduced by 1 b- increased by 1 C- reduced by 2 d- increased by 2
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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You must give answer to all the 3 questions.
![1- The degrees of freedom of an N-bar linkage containing only full revolute joints is ...
a- M = N-3
b- M = N+3
c- M = N-1
d- M = N-2
3- The mobility of a fourbar linkage that has only 4 full revolute joint is..
• a- M = 1
b- M = 2
C- M = 0
d- M = -1
8- If a binary link is removed from a fivebar linkage containing only full revolute joints, the mobility of
resulting linkage will be ..
a- reduced by 1
b- increased by 1
C- reduced by 2
d- increased by 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16d07802-c803-4f75-9a31-dccdd99637b5%2F1fdb2344-a46e-4d23-85b4-445a73ecb287%2Fjj5pdu6_processed.png&w=3840&q=75)
Transcribed Image Text:1- The degrees of freedom of an N-bar linkage containing only full revolute joints is ...
a- M = N-3
b- M = N+3
c- M = N-1
d- M = N-2
3- The mobility of a fourbar linkage that has only 4 full revolute joint is..
• a- M = 1
b- M = 2
C- M = 0
d- M = -1
8- If a binary link is removed from a fivebar linkage containing only full revolute joints, the mobility of
resulting linkage will be ..
a- reduced by 1
b- increased by 1
C- reduced by 2
d- increased by 2
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