1) The condensation reaction between a hydroxyl group and a carboxylic group is found to follow the following rate law: -d[COOH]/dt = -d[OH]/kt = K[COOH][OH] where K has the value of 10-2 L/mol sec. What is the conversion of carboxylic acid and number-average molecular weight of the polymers formed after 60 hours of reaction in the following systems. a) 1 mole of butoxyl acid HO(CH2)4COOH. Add solvent to make 10 liters. b) 0.47 mole of terephthalic acid HOOC-(C6H4)-COOH and 0.5 mole of ethylene glycol HO-CH2CH2-OH. Add solvent to make 10 liters. 1) The condensation reaction between a hydroxyl group and a carboxylic group is found to follow the following rate law: -d[COOH]/dt = -d[OH]/kt = K[COOH][OH] where K has the value of 10² L/mol sec. %3D What is the conversion of carboxylic acid and number-average molecular weight of the polymers formed after 60 hours of reaction in the following systems. a) 1 mole of butoxyl acid HO(CH2)4COOH. Add solvent to make 10 liters. b) 0.47 mole of terephthalic acid HOOC-(C,H4)-COOH and 0.5 mole of ethylene glycol HO-CH2CH2-OH. Add solvent to make 10 liters.

1) The condensation reaction between a hydroxyl group and a carboxylic group is found to follow the following rate law: -d[COOH]/dt = -d[OH]/kt = K[COOH][OH] where K has the value of 10-2 L/mol sec. What is the conversion of carboxylic acid and number-average molecular weight of the polymers formed after 60 hours of reaction in the following systems. a) 1 mole of butoxyl acid HO(CH2)4COOH. Add solvent to make 10 liters. b) 0.47 mole of terephthalic acid HOOC-(C6H4)-COOH and 0.5 mole of ethylene glycol HO-CH2CH2-OH. Add solvent to make 10 liters. 1) The condensation reaction between a hydroxyl group and a carboxylic group is found to follow the following rate law: -d[COOH]/dt = -d[OH]/kt = K[COOH][OH] where K has the value of 10² L/mol sec. %3D What is the conversion of carboxylic acid and number-average molecular weight of the polymers formed after 60 hours of reaction in the following systems. a) 1 mole of butoxyl acid HO(CH2)4COOH. Add solvent to make 10 liters. b) 0.47 mole of terephthalic acid HOOC-(C,H4)-COOH and 0.5 mole of ethylene glycol HO-CH2CH2-OH. Add solvent to make 10 liters.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Designing a Synthesis

Organic synthesis is a branch of chemical synthesis that involves the planned construction of organic compounds/molecules from smaller units that possess functional groups. Friedrich Wöhler was the first scientist who designed the synthesis of an organic compound, urea from inorganic starting materials silver cyanate with ammonium chloride via a simple, one-step synthesis.

Question

1) The condensation reaction between a hydroxyl group and a carboxylic group is found to follow the
following rate law: -d[COOH]/dt = -d[OH]/kt = K[COOH][OH] where K has the value of 10-2 L/mol sec.
What is the conversion of carboxylic acid and number-average molecular weight of the polymers formed
after 60 hours of reaction in the following systems. a) 1 mole of butoxyl acid HO(CH2)4COOH. Add solvent
to make 10 liters. b) 0.47 mole of terephthalic acid HOOC-(C6H4)-COOH and 0.5 mole of ethylene glycol
HO-CH2CH2-OH. Add solvent to make 10 liters.
1) The condensation reaction between a hydroxyl group and a carboxylic
group is found to follow the following rate law:
-d[COOHJ/dt = -d[OH]/kt = K[COOH][OH]
where K has the value of 102 L/mol sec.
What is the conversion of carboxylic acid and number-average
molecular weight of the polymers formed after 60 hours of reaction in
the following systems.
a) 1 mole of butoxyl acid HO(CH2)ĄCOOH. Add solvent to make 10
liters.
b) 0.47 mole of terephthalic acid HOOC-(C6H4)-COOH and 0.5 mole
of ethylene glycol HO-CH2CH2-OH. Add solvent to make 10
liters.

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