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1) The 10-kg cart is released from rest at time t = 0 on the inclined surface. The force P = 40t N acts on the cart, where t is the time measured in seconds. (a) Determine the distance the cart will move down the inclined surface before reversing direction. (b) Find the velocity of the cart when it returns to the point of release. P = 401 N 10 kg 20°

1) The 10-kg cart is released from rest at time t = 0 on the inclined surface. The force P = 40t N acts on the cart, where t is the time measured in seconds. (a) Determine the distance the cart will move down the inclined surface before reversing direction. (b) Find the velocity of the cart when it returns to the point of release. P = 401 N 10 kg 20°

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1) The 10-kg cart is released from rest at time t = 0 on the inclined surface. The force P 40t N acts on the cart, where t is the time measured in seconds. (a) Determine the distance the cart will move down the inclined surface before reversing direction. (b) Find the velocity of the cart when it returns to the point of release. %3D -P = 40t N 10 kg 20°
Transcribed Image Text:1) The 10-kg cart is released from rest at time t = 0 on the inclined surface. The force P 40t N acts on the cart, where t is the time measured in seconds. (a) Determine the distance the cart will move down the inclined surface before reversing direction. (b) Find the velocity of the cart when it returns to the point of release. %3D -P = 40t N 10 kg 20°
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