1- tan e 5) 1- tane sec* e-2 sec? 0+1 6) csc? 0 -1

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Complete simplify each problem so that no quotient is in the answer.

**Problem 5:**

\[
\frac{1 - \tan^3 \theta}{1 - \tan \theta}
\]

This expression involves simplifying a fraction where both the numerator and denominator include the tangent function of an angle \(\theta\). The numerator is \(1 - \tan^3 \theta\) and the denominator is \(1 - \tan \theta\).

**Problem 6:**

\[
\frac{\sec^4 \theta - 2\sec^2 \theta + 1}{\csc^2 \theta - 1}
\]

This expression involves a fraction. The numerator is a polynomial expression in terms of \(\sec \theta\), specifically \(\sec^4 \theta - 2\sec^2 \theta + 1\). The denominator is given as \(\csc^2 \theta - 1\).

There are no graphs or diagrams in this image, only algebraic expressions that require simplification or analysis using trigonometric identities.
Transcribed Image Text:**Problem 5:** \[ \frac{1 - \tan^3 \theta}{1 - \tan \theta} \] This expression involves simplifying a fraction where both the numerator and denominator include the tangent function of an angle \(\theta\). The numerator is \(1 - \tan^3 \theta\) and the denominator is \(1 - \tan \theta\). **Problem 6:** \[ \frac{\sec^4 \theta - 2\sec^2 \theta + 1}{\csc^2 \theta - 1} \] This expression involves a fraction. The numerator is a polynomial expression in terms of \(\sec \theta\), specifically \(\sec^4 \theta - 2\sec^2 \theta + 1\). The denominator is given as \(\csc^2 \theta - 1\). There are no graphs or diagrams in this image, only algebraic expressions that require simplification or analysis using trigonometric identities.
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