1) Suppose random variable X - N(2,4) (normal distribution with mean 2 and variance 4).Suppose random variable Y follows the distribution below (0 and 1 are the only two possibleoutcomes for Y):(0.4Pr(Y %3D у) —(0.6What is Pr(X=1) and Pr(Y=1) respectively?y = 0y = 1

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Answered: 1) Suppose random variable X - N(2,4)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If Y is Normally distributed , and p(y < 170 ) = 0.14 p ( y > 200 ) = 0.03 then the values of the mean and variance of Y , respectively are
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A: 98, 100,93,71,73,79,89,82,82,84,79,71,91,72 B: 15,33,16,40,30,34,31,38,29,28,24 calculate coeffecient of variation,CV,Round to one decimal place.
13. STATEMENTS FIRST: CORRELATION CAN BE USED TO DETERMINE THE DEGREE OF RELATIONSHIP BETWEEN VARIABLES SECOND: COEFFICIENT CORRELATION RANGES FROM 0-1A. IF BOTH STATEMENTS ARE TRUEB. IF BOTH STATEMENTS ARE FALSEC. IF THE FIRST IS TRUE AND THE SECOND IS FALSED. IF THE FIRST IS FALSE AND THE SECOND IS TRUE 14. STATEMENTS FIRST; STANDARD DEVIATION IS THE SQUARE ROOT OF THE VARIANCE SECOND: DISPERSION GIVES US THE IDEA OF THE DEGREE OF SCATTERING OF THE DATA IN THE DISTRIBUTION A. IF BOTH STATEMENTS ARE TRUEB. IF BOTH STATEMENTS ARE FALSEC. IF THE FIRST IS TRUE AND THE SECOND IS FALSED. IF THE FIRST IS FALSE AND THE SECOND IS TRUE 15. CHARACTERISTICS OF THE NORMAL CURVEI. CURVE IS ASYMMETRICAL ABOUT MEANII. TAILS OF THE NORMAL CURVE ARE ASYMPTOTIC RELATIVE TO THE HORIZONTAL LINEIII. TOTAL AREA UNDER THE NORMAL CURVE IS EQUAL TO 1IV. NORMAL CURVE ARE SUBDIVIDED INTO THE THREE STANDARD DEVIATION A. I, II, AND III ONLYB. II, III, AND IV ONLYC. I, II, III, AND IVD. I, II, AND IV ONLYE. I,…
A certain IQ test is known to have a population mean of 100 and standard deviation of 15 in the general population. You want to test whether psychology majors have a different average IQ than the population as a whole. Assume the variance of IQ is the same for Psych majors as it is in the general population. Suppose that Psychology majors actually have an average IQ of 108. If you do a 2-tailed test at α= .05 with a sample of 56 Psychology majors, you will be able to reject the null hypothesis if the mean IQ of your sample is below [L] or above [H]. Find L and H values. Options listed below. [L] answer choices: 96.08, 98.00, 103.92, 104.08, 110.00, 111.92. [H] Answer choices: 96.08, 98.00, 103.92, 104.08, 110.00, 111.92.
5. A quality control engineer found that the inner and outer diameters of their ball bearings, denoted respectively as X and Y, are random variables with E(X|Y = y) = 0.7 – 0.3y inches and Var(X|Y = y) = 0.0004y for all values of y. From his past experience he also knew that the mean and variance of the outer diameters were E(Y) = 0.7 inches, and Var(Y) squared inches. = 0.0001 %3D • (i) What are the conditional random variables, E(X|Y) and Var(X|Y)? • (ii) Find the mean of the inner diameters, E(X). • (ii) Find the variance of the inner diameters, Var(X).
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Compute the standard score (Z-score) for x, when x = 21, the mean of the distribution = 27, and the variance (S2) = 9. Z = %3D O 2 -2 .67 -.67
An experiment where a patient's blood pressure is measured before a treatment (call it X;) and after the treatment (call it Y;). The difference in the blood pressue of each patient, Z; = Y; – X; is also recorded. The sample size n of patients is large. Suppose the true population mean of the patient's blood pressure before treatment is 41 and after treatment is 42, both unknown. Suppose the true population variance of the patient's blood pressue before and after treatment are the same, but unknown. Find an approximate 1-a confidence interval for 12 - 41- 2.

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1) Suppose random variable X - N(2,4) (normal distribution with mean 2 and variance 4). Suppose random variable Y follows the distribution below (0 and 1 are the only two possible outcomes for Y): (0.4 Pr(Y = y) = (0.6 What is Pr(X=1) and Pr(Y=1) respectively? y = 0 y = 1