(1) SOL (2) SLL Calculate the Long-term deflection assuming that 25% of the live load is Continuously applied for 3 years. 8-#8. (3) (4) DL+LL

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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### Structural Engineering Calculation for Long-term Deflection

#### Diagram and Load Details
- **Diagram**: A schematic shows a beam fixed at one end with a point load (P<sub>LL</sub> = 20k) at the free end. The span is 15 feet.
- **Load Information**:
  - w<sub>DL</sub> = 2.0 KLF (including self-weight)
  - f’<sub>c</sub> = 4000 psi, Normal Weight Concrete (NWC)
  - Grade 60 steel

#### Steps for Calculation

1. **Identification of Loads**:
   - S<sub>DL</sub> for dead load
   - S<sub>LL</sub> for live load
   - S<sub>DL+LL</sub> for combined dead and live load

2. **Long-term Deflection Calculation**:
   - Assume 25% of the live load is continuously applied for 3 years.

3. **Material Properties**:
   - E<sub>C</sub> = 57000√(f’<sub>c</sub>)
   - E<sub>C</sub> = 3600 ksi
   - λ = 1, Normal Weight Concrete (NWC)
   - Cover = 1.5 inches
   - Modular ratio, n = E<sub>s</sub>/E<sub>C</sub> = 8

4. **Section Properties and Reinforcement**:
   - Effective depth, d = 36 - 1.5 - 0.5 - 8/8 - 1/2 = 32.5 inches
   - Moment of Inertia, I<sub>g</sub> = 1/12 × 16 × 36³ = 62208 in<sup>4</sup>

5. **Flexural Strength**:
   - f<sub>r</sub> = 7.5 λ √(f’<sub>c</sub>) = 474.3 psi
   - λ = 1.0

#### Reinforcement Diagram
- A cross-section sketch represents reinforcement:
  - 8 bars of #8 steel on the top
  - #4 bar at the bottom
  - Overall dimensions: 36" height, 16" width

This calculation provides insights into beam deflection and strength, considering
Transcribed Image Text:### Structural Engineering Calculation for Long-term Deflection #### Diagram and Load Details - **Diagram**: A schematic shows a beam fixed at one end with a point load (P<sub>LL</sub> = 20k) at the free end. The span is 15 feet. - **Load Information**: - w<sub>DL</sub> = 2.0 KLF (including self-weight) - f’<sub>c</sub> = 4000 psi, Normal Weight Concrete (NWC) - Grade 60 steel #### Steps for Calculation 1. **Identification of Loads**: - S<sub>DL</sub> for dead load - S<sub>LL</sub> for live load - S<sub>DL+LL</sub> for combined dead and live load 2. **Long-term Deflection Calculation**: - Assume 25% of the live load is continuously applied for 3 years. 3. **Material Properties**: - E<sub>C</sub> = 57000√(f’<sub>c</sub>) - E<sub>C</sub> = 3600 ksi - λ = 1, Normal Weight Concrete (NWC) - Cover = 1.5 inches - Modular ratio, n = E<sub>s</sub>/E<sub>C</sub> = 8 4. **Section Properties and Reinforcement**: - Effective depth, d = 36 - 1.5 - 0.5 - 8/8 - 1/2 = 32.5 inches - Moment of Inertia, I<sub>g</sub> = 1/12 × 16 × 36³ = 62208 in<sup>4</sup> 5. **Flexural Strength**: - f<sub>r</sub> = 7.5 λ √(f’<sub>c</sub>) = 474.3 psi - λ = 1.0 #### Reinforcement Diagram - A cross-section sketch represents reinforcement: - 8 bars of #8 steel on the top - #4 bar at the bottom - Overall dimensions: 36" height, 16" width This calculation provides insights into beam deflection and strength, considering
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