What can we replace lines 21 and 22 with? 1READING CODE - STACK47list the output of the following program assuming the input is as follows:3101mov al, 0; Return code of 0mov ah, 4ch: Exit back to MSDOS4849423250int 21hMain ENDP548511752753Data; re-enter the data segment for this procedureinclude PCMAC.INC54NEWLINE EQU_PutCh 13, 10MessageSubMystery55DB 'Enter a number $'1056DW ?11MODEL SMALL5712STACK 100hDATACODE ; return to coding581359Messagel DB 'Total sold today, S'Message2 DB , is: $'Sublnput PROCmov cx, 4146015611662myLoop:1763CODEEXTERN GetDec: NEAR, PutDec NEARPutStr MessageSubcall GetDecadd Mystery, ax1864196520Main PROC66dec cxinz myLoopmov ax, Mystery21mov ax, @datads, axGetDatepush cxpush dxpush dxcall Sublnput send control to subproceduremov bx, axPutStr Messagel6722mov682369ret24702571Sublnput ENDP267273END Main; Tells where to start execution287475рop dxmov al, dhmov ah, 0call PutDecPutCh "pop dxmov al, dlmov ah, 0call PutDec76313233343536373839_PutCh "40рop сх41mov ax, cxcall PutDec_PutStr Message242434445mov ax, bxcall PutDecNEWLINE46

1 READING CODE - STACK ;list the output of the following program assuming the input is as follows: 101 3 4 232 5 48 6. 17 7 include PCMAC.INC NEWLINE EQU_PutCh 13, 10 10 MODEL SMALL STACK 100h DATA 11 12 13 14 Messagel DB 'Total sold today, S 15 Message2 DB , is: S' 16 17 18 CODE EXTERN GetDec: NEAR, PutDec:NEAR 19 20 Main PROC 21 mov ax, @data ds, ax 22 mov

1 READING CODE - STACK ;list the output of the following program assuming the input is as follows: 101 3 4 232 5 48 6. 17 7 include PCMAC.INC NEWLINE EQU_PutCh 13, 10 10 MODEL SMALL STACK 100h DATA 11 12 13 14 Messagel DB 'Total sold today, S 15 Message2 DB , is: S' 16 17 18 CODE EXTERN GetDec: NEAR, PutDec:NEAR 19 20 Main PROC 21 mov ax, @data ds, ax 22 mov

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please answer with explanation. ASAP. I will really upvote. Thanks
Consider all bit (binary digit) strings of length 12. How many begin with 110? How many begin with 11 and end with 10? How many begin with 11 or end with 10? How many have exactly four 1s?
ʙᴇʟᴏᴡ ɪꜱ ʜᴏᴡ ᴛʜᴇ ꜰɪʟᴇɴᴀᴍᴇꜱ ᴀʀᴇ ʀᴇᴘʀᴇꜱᴇɴᴛᴇᴅᴀʀʀᴀʏ[] = [50, 11, 33, 21, 40, 50, 40, 40, 21]ʙᴇʟᴏᴡ ɪꜱ ᴛʜᴇ ᴇxᴘᴇᴄᴛᴇᴅ ᴏᴜᴛᴘᴜᴛ ᴀꜰᴛᴇʀ ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴᴀʀʀᴀʏ[] = [11, 21, 33, 40, 50] ʏᴏᴜ ᴄᴀɴɴᴏᴛ ᴜꜱᴇ ʟɪʙʀᴀʀʏ ꜰᴜɴᴄᴛɪᴏɴꜱ ᴛᴏ ᴇɪᴛʜᴇʀꜱᴏʀᴛ ᴀɴᴅ ᴏʀ ᴘᴇʀꜰᴏʀᴍ ᴛʜᴇ ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴ ᴏᴘᴇʀᴀᴛɪᴏɴ. ɪɴ ᴊᴀᴠᴀ ɪᴍᴘʟᴇᴍᴇɴᴛ ᴛʜᴇ ꜰᴜɴᴄᴛɪᴏɴ ɪɴ ꜱᴜᴄʜ ᴀ ᴡᴀʏ ᴛʜᴀᴛ ʏᴏᴜʀ ꜱᴏʟᴜᴛɪᴏɴ ꜱᴏʟᴠᴇꜱᴛʜᴇ ᴘʀᴏʙʟᴇᴍ ᴡɪᴛʜ ᴏ(ɴ ʟᴏɢ2(ɴ)) ᴛɪᴍᴇ ᴄᴏᴍᴘʟᴇxɪᴛʏ ᴏᴠᴇʀᴀʟʟ ʙᴜᴛ ꜱᴛᴀʏꜱ ᴡɪᴛʜɪɴ ᴛʜᴇ ʙᴏᴜɴᴅꜱ ᴏꜰ ᴏ(1) ꜱᴘᴀᴄᴇ ᴄᴏᴍᴘʟᴇxɪᴛʏ. ʜᴇʀᴇ, ɴ ɪꜱ ᴛʜᴇ ʟᴇɴɢᴛʜ ᴏꜰ ᴛʜᴇ ʟɪꜱᴛ ᴏꜰɪɴᴘᴜᴛ ɪɴᴛᴇɢᴇʀꜱ (ᴀʀʀᴀʏ). ɪ ʙᴇʟɪᴇᴠᴇ ᴛʜᴇ ꜱᴏʀᴛɪɴɢ ʀᴏᴜᴛɪɴᴇ ᴛʜᴀᴛ ᴄᴀɴ ʙᴇ ᴜꜱᴇᴅ ʜᴇʀᴇ ɪꜱ Qᴜɪᴄᴋ ꜱᴏʀᴛ. ᴘʟᴇᴀꜱᴇ ꜱᴛᴀᴛᴇ ᴀꜱ ᴄᴏᴅᴇ ᴄᴏᴍᴍᴇɴᴛ ᴡʜɪᴄʜ ꜱᴏʀᴛɪɴɢ ʀᴏᴜᴛɪɴᴇ ʏᴏᴜ ᴀʀᴇ ᴜꜱɪɴɢ, ꜱᴏʀᴛ ᴛʜᴇ ᴀʀʀᴀʏ ᴡɪᴛʜ ᴛʜᴀᴛ ᴀʟɢᴏʀɪᴛʜᴍ ᴀɴᴅ ꜱᴏʟᴠᴇ ᴛʜᴇ ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴ ᴘʀᴏʙʟᴇᴍ ᴛʜᴇʀᴇᴀꜰᴛᴇʀ. ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴ ᴘᴀʀᴛ ᴏꜰ ᴛʜᴇ ꜱᴏʟᴜᴛɪᴏɴ ɪɴ ɪᴛꜱᴇʟꜰ ᴍᴜꜱᴛ ᴀᴅʜᴇʀᴇ ᴛᴏ ᴏ(ɴ) ᴛɪᴍᴇ ᴀɴᴅ ᴏ(1) ꜱᴘᴀᴄᴇ ʙᴏᴜɴᴅꜱ ᴄᴏᴍᴍᴇɴᴛ ᴇᴠᴇʀʏ ʟɪɴᴇ ᴏꜰ ᴄᴏᴅᴇᴘʟᴇᴀꜱᴇ ᴡʀɪᴛᴇ ᴛᴇꜱᴛ-ᴄᴀꜱᴇꜱ ᴏɴ ʜᴏᴡ ᴏɴᴇ ᴡᴏᴜʟᴅᴛᴇꜱᴛ ᴛʜᴇ ꜱᴏʟᴜᴛɪᴏɴ ᴀꜱꜱᴜᴍᴘᴛɪᴏɴꜱ ᴀɴᴅ ʜᴇɴᴄᴇ ᴛʜᴇ ᴄᴏᴅᴇ ᴇxᴀᴍᴘʟᴇ ᴏꜰ ᴄᴀꜱᴇꜱ ᴛᴏ ʙᴇ ᴛᴇꜱᴛᴇᴅ ꜰᴏʀ ᴀʀᴇ ʟɪᴋᴇ : ᴡʜᴀᴛ ɪꜰ ᴛʜᴇ ᴀʀʀᴀʏ ɪɴᴘᴜᴛ ᴡʜɪᴄʜɪꜱ…
Give the post order traversal of the BST
How many bit strings of length 10 begin and end with '11'?
The ROT-13 algorithm encrypts a string one character at a time by adding 13 to the value of the internal representation of the character. We want our encryption scheme to cover the entire printable ASCII range. After examining the ASCII character set and their internal representations, we see that characters 0 through 32 and character 127 are control characters. Technically, characters 32 (space) and 127 (DEL) are printable, but we don’t want to include them in our encryption routine. Therefore, we want our encrypted string to only contain characters in the range of 33 through 126. As an example: Plaintext: Norwich Ciphertext: [|!&vpu The internal representation of ‘N’ is 78. 78 plus 13 is 91, which is the character ‘[‘. The internal representation of ‘o’ is 111. 111 plus 13 is 124, which is the character ‘|’. The internal representation of ‘r’ is 114. 114 plus 13 is 127. Since 126 is our maximum value for our desired printable range, we…
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