(1 point) Let y = f(x) = 6√√x+1-5. When we are computing what happens to x, we first add 1 to x, then take the square root, and so on. Represent this chain of computations visually by labeling the arrows in the diagram below. (In the possible answers below, let '?' be the result from the previous step.) A.1 A.2 A.3 0-0-0-0-0 A.1 A. ?+1 B. 6x? □ C. √(?) D. ?-5 A.2 A.3 A. √(?) B. ?+1 C. 6x? D.? 5 A. 6x? B. ?+1 C.?-5 D. √(?) A.3 A. 6x? ☐ B. ?+1 ☐ C. ? - 5 OD. √(?) A.4 A. 6x? OB. √(?) ☐ C. ?-5 D. ?+1 b) Now, reverse these steps. This is essentially solving for y. A.4 in Reverse A. ?² ☐ B. ?/6 ☐ C. ?-1 ☐ D. ? +5 A.3 in Reverse A. ? +5 ☐ B. ?² ☐ C. ?-1 ☐ D. ?/6 A.2 in Reverse Π.Α. 0/6 ☐ B. ? +5 ☐ C. ?-1 D. ?2 A.1 in Reverse A. ?2 B. ?/6 ☐ C. ? +5 D. ?-1 c) Using the steps you identified in part b), write a formula for f-1 (y). f-l() =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 28RE
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djdjjdjdk4jr i need help on part C,
(1 point) Let y = f(x) = 6√√x+1-5. When we are computing what happens to x, we first add 1 to x, then take the square root, and so on. Represent this chain of computations
visually by labeling the arrows in the diagram below. (In the possible answers below, let '?' be the result from the previous step.)
A.1
A.2
A.3
0-0-0-0-0
A.1
A. ?+1
B. 6x?
□ C. √(?)
D. ?-5
A.2
A.3
A. √(?)
B. ?+1
C. 6x?
D.? 5
A. 6x?
B. ?+1
C.?-5
D. √(?)
Transcribed Image Text:(1 point) Let y = f(x) = 6√√x+1-5. When we are computing what happens to x, we first add 1 to x, then take the square root, and so on. Represent this chain of computations visually by labeling the arrows in the diagram below. (In the possible answers below, let '?' be the result from the previous step.) A.1 A.2 A.3 0-0-0-0-0 A.1 A. ?+1 B. 6x? □ C. √(?) D. ?-5 A.2 A.3 A. √(?) B. ?+1 C. 6x? D.? 5 A. 6x? B. ?+1 C.?-5 D. √(?)
A.3
A. 6x?
☐ B. ?+1
☐ C. ? - 5
OD. √(?)
A.4
A. 6x?
OB. √(?)
☐ C. ?-5
D. ?+1
b) Now, reverse these steps. This is essentially solving for y.
A.4 in Reverse
A. ?²
☐ B. ?/6
☐ C. ?-1
☐ D. ? +5
A.3 in Reverse
A. ? +5
☐ B. ?²
☐ C. ?-1
☐ D. ?/6
A.2 in Reverse
Π.Α. 0/6
☐ B. ? +5
☐ C. ?-1
D. ?2
A.1 in Reverse
A. ?2
B. ?/6
☐ C. ? +5
D. ?-1
c) Using the steps you identified in part b), write a formula for f-1 (y).
f-l() =
Transcribed Image Text:A.3 A. 6x? ☐ B. ?+1 ☐ C. ? - 5 OD. √(?) A.4 A. 6x? OB. √(?) ☐ C. ?-5 D. ?+1 b) Now, reverse these steps. This is essentially solving for y. A.4 in Reverse A. ?² ☐ B. ?/6 ☐ C. ?-1 ☐ D. ? +5 A.3 in Reverse A. ? +5 ☐ B. ?² ☐ C. ?-1 ☐ D. ?/6 A.2 in Reverse Π.Α. 0/6 ☐ B. ? +5 ☐ C. ?-1 D. ?2 A.1 in Reverse A. ?2 B. ?/6 ☐ C. ? +5 D. ?-1 c) Using the steps you identified in part b), write a formula for f-1 (y). f-l() =
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