" (۱- " ) " | = 1 ton (2) (sec² (2)-1) sec² (2) dx له ( * - ) | = ۔ 8 8 u s 5 sects) - Sec (x) 8 + C ا Sec s tan³ (x) secº(x) dx = C l+C Let u = sec (x) du= tan (x) sec(x) dx
" (۱- " ) " | = 1 ton (2) (sec² (2)-1) sec² (2) dx له ( * - ) | = ۔ 8 8 u s 5 sects) - Sec (x) 8 + C ا Sec s tan³ (x) secº(x) dx = C l+C Let u = sec (x) du= tan (x) sec(x) dx
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![= √ √²
5
√ tua 17) (sec² (1)-1) see² (1) de
dx
(x)
}|
(u² -1) du
= √ (w² - w²³) du
5
48 и
8
5
с
[ =
tan³ (x) sec (x) dx
=
8
sec ³(x) _ Sec ³
5
+C
Let u= sec (X)
du= tan (x) sec(x) dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ce5a312-47f5-4ea5-9943-a91071c93119%2Ff89c1949-0d89-48a7-8d22-bc0491261c44%2Fh35e079_processed.jpeg&w=3840&q=75)
Transcribed Image Text:= √ √²
5
√ tua 17) (sec² (1)-1) see² (1) de
dx
(x)
}|
(u² -1) du
= √ (w² - w²³) du
5
48 и
8
5
с
[ =
tan³ (x) sec (x) dx
=
8
sec ³(x) _ Sec ³
5
+C
Let u= sec (X)
du= tan (x) sec(x) dx
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