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1 name ('Mary') 2 password = 'swordfish' 3 if name == Mary: 4 5 6 7 8 = print ('Hello, Mary') if password == 'swordfish': print (Access granted.') else: print ('Wrong password.') I

1 name ('Mary') 2 password = 'swordfish' 3 if name == Mary: 4 5 6 7 8 = print ('Hello, Mary') if password == 'swordfish': print (Access granted.') else: print ('Wrong password.') I

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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What is causing  this error

Mu 1.1.1- new practice.py r Mode blank.py om/ all ne i 1 2 ord.' 3 4 5 6 7 8 New Load Save >>> X new practice.py X Running: new practice.py name = password if name ('Mary') = X it Stop Debug REPL == 'swordfish' ↑ Mary: print (Hello, Mary') if password == 'swordfish': print (Access granted.') else: print ('Wrong password.') I Plotter Zoom-in Q File "c:\users\johnc\mu_code\new practice.py", line 3 if name == Mary: A IndentationError: unexpected indent Zoom-out Th
Transcribed Image Text:Mu 1.1.1- new practice.py r Mode blank.py om/ all ne i 1 2 ord.' 3 4 5 6 7 8 New Load Save >>> X new practice.py X Running: new practice.py name = password if name ('Mary') = X it Stop Debug REPL == 'swordfish' ↑ Mary: print (Hello, Mary') if password == 'swordfish': print (Access granted.') else: print ('Wrong password.') I Plotter Zoom-in Q File "c:\users\johnc\mu_code\new practice.py", line 3 if name == Mary: A IndentationError: unexpected indent Zoom-out Th
Expert Solution
Step 1

indentation is important in python make sure you give correct indentation

in your program 

you have to write string in quotes in line 3 

  • if name == 'Mary'

the correct code see below

 

steps

Step by step

Solved in 3 steps with 2 images

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