1-mey a Ed found that the average fer all Students who feel that good manners are naessary to be 75wAh Stardarol devration. of 251 Assume they tuk a random This data is namally distmatcd. Sampie of 64 Studen ts Find the probabıllty that the average numberdE Students that Shere this view Is mee than 78 Students O find the pr bability that the averaje anumberof stucdents that share this view is between 65 and 3

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### Statistical Analysis of Student Views on Good Manners

1. **Research Background:**
   - A study conducted by a group (indicated as "mey a Ed") found that the average number of students who believe good manners are necessary is 75. This data is normally distributed with a standard deviation of 25. A random sample of 64 students was taken.

2. **Problem Statements:**
   - **(a)** Calculate the probability that the average number of students who share this view is more than 78.
   - **(b)** Determine the probability that the average number of students who share this view is between 65 and 72.

### Explanation of Diagrams
There are no graphs or diagrams in the image provided. The focus is on statistical calculations concerning the normal distribution of student opinions.
Transcribed Image Text:### Statistical Analysis of Student Views on Good Manners 1. **Research Background:** - A study conducted by a group (indicated as "mey a Ed") found that the average number of students who believe good manners are necessary is 75. This data is normally distributed with a standard deviation of 25. A random sample of 64 students was taken. 2. **Problem Statements:** - **(a)** Calculate the probability that the average number of students who share this view is more than 78. - **(b)** Determine the probability that the average number of students who share this view is between 65 and 72. ### Explanation of Diagrams There are no graphs or diagrams in the image provided. The focus is on statistical calculations concerning the normal distribution of student opinions.
Expert Solution
Step 1

a)

The Z-score of a random variable X is defined as follows:

Z = (X – µ)/σ.

Here, µ and σ are the mean and standard deviation of X, respectively.

Step 2

Consider a random variable X, that defines the number of students, who feel that good manners are necessary.

According to the given information, X have mean µx = 75 and the standard deviation of σ x = 25.

According to central limit theorem, for large sample (>30) or if the population follows normal distribution, then the sampling distribution of the sample mean follows normal distribution with the expectation and standard deviation defined as follows:

E() = µ and SD() = σ/√n.

Here, n is the sample size, µ is the population mean and σ is the population standard deviation of the random variable X.

Consider that is the sample mean.

Now, for sample of 64, the mean of the sampling distribution of the sample mean is,

µ = 75.

Now, for sample of 64, the standard deviation of the sampling distribution of the sample mean is,

σ = 25/√64

     = 3.125.

Thus, the sampling distribution of is approximately normal with mean µ = 75 and standard deviation σ = 3.125.

The probability that the average number of students that show this view is more than 78 students is,

Statistics homework question answer, step 2, image 1

Therefore, the probability that the average number of students that show this view is more than 78 students is 0.1685.

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