Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
1 Method of Images 1. Write down the potential V(x, y, z) due to a point charge q at z = 2, and q, at z = z, (assume z, > 2; for your diagram).

1 Method of Images 1. Write down the potential V(x, y, z) due to a point charge q at z = 2, and q, at z = z, (assume z, > 2; for your diagram).

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
1 Method of Images 1. Write down the potential v (2, y, z) due to a point charge q; at z = z; and q. at z = z. (assume z, > 2; for your diagram). 2. Show that the choices of q = -q.(R/z,) and z, = R2/z, give v (r = R) = 0. That is, with these choices for q and z,, this potential is zero on a sphere centered on the origin and with a radius R. Once you have found v(z, y, 2) due this two-charge problem, you have solved another problem: The potential due to a point charge outside of a grounded (v = 0) conducting sphere of radiusR that is centered on the origin. The boundary conditions for the conductor problem is that v is zero on the surface of the sphere and approaches zero as r → ∞. The v for the two-charge problem matches these boundary conditions and so the two-charge v must be the same as the v for the conductor problem.
Transcribed Image Text:1 Method of Images 1. Write down the potential v (2, y, z) due to a point charge q; at z = z; and q. at z = z. (assume z, > 2; for your diagram). 2. Show that the choices of q = -q.(R/z,) and z, = R2/z, give v (r = R) = 0. That is, with these choices for q and z,, this potential is zero on a sphere centered on the origin and with a radius R. Once you have found v(z, y, 2) due this two-charge problem, you have solved another problem: The potential due to a point charge outside of a grounded (v = 0) conducting sphere of radiusR that is centered on the origin. The boundary conditions for the conductor problem is that v is zero on the surface of the sphere and approaches zero as r → ∞. The v for the two-charge problem matches these boundary conditions and so the two-charge v must be the same as the v for the conductor problem.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS