1 lim x cos- #48 X lim 00-00 = lim 20-00 cos (1/x) 1/x [-sin (1/x)] (1/2) -1/x² =lim sin 22-00 = 0 1 x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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82. Please solve this ASAP, L’Hôpital’s Rule is used incorrectly. Describe the error.

 

PLEASE TYPE OUT the answer, do not handwrite thanks. 

1
lim x cos -
x
lim
x+00
lim
x →00
cos(1/x)
1/x
= 0
[-sin(1/x)](1/x²)
-1/x²
1
=lim sin.
x+00
Transcribed Image Text:1 lim x cos - x lim x+00 lim x →00 cos(1/x) 1/x = 0 [-sin(1/x)](1/x²) -1/x² 1 =lim sin. x+00
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