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(1) Let C₁ and C₂ be arbitrary constants. The general solution to the homogeneous differential equation a²y" - 17xy' +81y = 0 is the function y(x) = C₁ y₁ (x) + C₂ Y2(x) = C₁ +C₂ (2) The unique solution to the initial value problem is the function y(x) = for 2 € For -∞ type -inf and for ∞ type inf. x²y" 17xy' +81y = 0, y(1) = 7, y'(1) = -3.

(1) Let C₁ and C₂ be arbitrary constants. The general solution to the homogeneous differential equation a²y" - 17xy' +81y = 0 is the function y(x) = C₁ y₁ (x) + C₂ Y2(x) = C₁ +C₂ (2) The unique solution to the initial value problem is the function y(x) = for 2 € For -∞ type -inf and for ∞ type inf. x²y" 17xy' +81y = 0, y(1) = 7, y'(1) = -3.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(1) Let C₁ and C₂ be arbitrary constants. The general solution to the homogeneous differential equation x²y" - 17xy' +81y = 0 is the function y(x) = C₁ y₁(x) + C₂ Y2(x) = C₁ +C₂ (2) The unique solution to the initial value problem is the function y(x) = for a € For -∞ type -inf and for x type inf. x²y" - 17xy' +81y = 0, y(1) = 7, y'(1) = −3.
Transcribed Image Text:(1) Let C₁ and C₂ be arbitrary constants. The general solution to the homogeneous differential equation x²y" - 17xy' +81y = 0 is the function y(x) = C₁ y₁(x) + C₂ Y2(x) = C₁ +C₂ (2) The unique solution to the initial value problem is the function y(x) = for a € For -∞ type -inf and for x type inf. x²y" - 17xy' +81y = 0, y(1) = 7, y'(1) = −3.
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