HI could you solve this,Thank you A1) Let=1 -33 -703-3 28-5 8-6 6 4Solve the matrix equation Ax = 0, and write the solution in parametric vector form.We know that the vectore is a solution to the equation Axall the solutions to the equation Ax = b in parametric vector form.=2= b. Write down

Answered: 1) Let A = 1 -3 4 -3 2 3 -7 8 -58 0 3…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

HI could you solve this,Thank you

A
1) Let
=
1 -3
3 -7
0
3
-3 2
8
-5 8
-6 6 4
Solve the matrix equation Ax = 0, and write the solution in parametric vector form.
We know that the vectore is a solution to the equation Ax
all the solutions to the equation Ax = b in parametric vector form.
=
2
= b. Write down

Expert Solution

Step 1: Row-echelon form

Since there are two questions, find the solution of the first one.

The matrix equation $A x equals 0$

Applying the elemetory transformations

$A equals open square brackets table row 1 cell negative 3 end cell 4 cell negative 3 end cell 2 row 3 cell negative 7 end cell 8 cell negative 5 end cell 8 row 0 3 cell negative 6 end cell 6 4 end table close square brackets R subscript 2 minus greater than R subscript 2 minus 3 R subscript 1 tilde open square brackets table row 1 cell negative 3 end cell 4 cell negative 3 end cell 2 row 0 cell negative 1 end cell cell negative 4 end cell 4 2 row 0 3 cell negative 6 end cell 6 4 end table close square brackets R subscript 3 minus greater than R subscript 3 plus 3 R subscript 2 tilde open square brackets table row 1 cell negative 3 end cell 4 cell negative 3 end cell 2 row 0 cell negative 1 end cell cell negative 4 end cell 4 2 row 0 0 cell negative 18 end cell 18 10 end table close square brackets R subscript 3 minus greater than fraction numerator negative 1 over denominator 18 end fraction R subscript 3 tilde open square brackets table row 1 cell negative 3 end cell 4 cell negative 3 end cell 2 row 0 cell negative 1 end cell cell negative 4 end cell 4 2 row 0 0 1 cell negative 1 end cell cell bevelled fraction numerator negative 5 over denominator 9 end fraction end cell end table close square brackets$

The row-echelon form.

In equation form