(1) L (abick: i, j, k≥ 0 and j = k} OS -> AK A-> aA A-> € K -> bkc S-> AK A-> aA K-> bkc K-> € OS -> AK A-> aA A-> € K-> bkc K-> € S -> AK A -> aA A -> a K-> bkc K-> bc
(1) L (abick: i, j, k≥ 0 and j = k} OS -> AK A-> aA A-> € K -> bkc S-> AK A-> aA K-> bkc K-> € OS -> AK A-> aA A-> € K-> bkc K-> € S -> AK A -> aA A -> a K-> bkc K-> bc
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question

Transcribed Image Text:Show a context-free grammar for each of the following languages.
Example 1: {a bm: m > n, m-n is even}
Context-free grammar for the language:
S -> aSb
S -> Sbb
S-> €
Example 2: {albi: i, j ≥ 0 and 2i = 3j + 1}
Context-free grammar for the language:
S->aaaSbb
S -> aab

Transcribed Image Text:(1) L = {albick: i, j, k ≥ 0 and j = k}
OS -> AK
A -> aA
A-> €
K-> bkc
S -> AK
A -> aA
K-> bkc
K-> €
OS -> AK
A -> aA
A -> €
K-> bkc
K-> €
S -> AK
A -> aA
A -> a
K-> bkc
K-> bc
Expert Solution

Step 1: Here is the conceptual introduction of the code:
The language L = {a^ib^jc^k : i, j, k ≥ 0 and j = k} consists of strings with equal numbers of b s and c s, preceded by zero or more a s. The grammar for this language can be generated using a context-free grammar.
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