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1 (In (n)) It is not possible to use the Direct Comparison Test to determine the convergence or divergence of Draw a conclusion about the convergence of Because 21- IMBIMB 114 115 n converges, also converges by the Direct Comparison Test. (In (n)) Because is a harmonic series, it diverges. Therefore, (In (n)) (In (n)) diverges by the Direct Comparison Test.

1 (In (n)) It is not possible to use the Direct Comparison Test to determine the convergence or divergence of Draw a conclusion about the convergence of Because 21- IMBIMB 114 115 n converges, also converges by the Direct Comparison Test. (In (n)) Because is a harmonic series, it diverges. Therefore, (In (n)) (In (n)) diverges by the Direct Comparison Test.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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For all a > 0 and b> 1, the inequalities In (n) ≤n", n < b are true for n sufficiently large (this can be proved using L'Hôpital's Rule). Let N be this sufficiently large n. Write an inequality comparing (In (n)) and n for n > N. (Express numbers in exact form. Use symbolic notation and fractions where needed.) inequality: 11 Incorrect Draw a conclusion about the convergence of Σ Because 00 It is not possible to use the Direct Comparison Test to determine the convergence or divergence of n=1 (n(n))8 1- =1 n converges, 00 Σ #=1 (In (n))* (In (n)) also converges by the Direct Comparison Test. Because is a harmonic series, it diverges. Therefore, 11 00 (In (n)) (In (n)) diverges by the Direct Comparison Test.
Transcribed Image Text:For all a > 0 and b> 1, the inequalities In (n) ≤n", n < b are true for n sufficiently large (this can be proved using L'Hôpital's Rule). Let N be this sufficiently large n. Write an inequality comparing (In (n)) and n for n > N. (Express numbers in exact form. Use symbolic notation and fractions where needed.) inequality: 11 Incorrect Draw a conclusion about the convergence of Σ Because 00 It is not possible to use the Direct Comparison Test to determine the convergence or divergence of n=1 (n(n))8 1- =1 n converges, 00 Σ #=1 (In (n))* (In (n)) also converges by the Direct Comparison Test. Because is a harmonic series, it diverges. Therefore, 11 00 (In (n)) (In (n)) diverges by the Direct Comparison Test.
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