[1] In basic solution balance the redox reaction MnO, (aq) MnO, (aq) MnO2(s) Final balanced reaction equation:

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Chapter1: Chemical Foundations
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**Balancing Redox Reactions and Calculating Cell Potentials**

**[1] In basic solution, balance the redox reaction:**

\[ \text{MnO}_4^{2-} (aq) \rightarrow \text{MnO}_4^{-} (aq) + \text{MnO}_2 (s) \]

**Final balanced reaction equation:**

*Provide the balanced equation here.*

---

**[2] In acidic solution, balance the redox reaction:**

\[ \text{Xe} (g) + \text{Cr}_2\text{O}_7^{2-} (aq) \rightarrow \text{XeO}_3 (s) + \text{Cr}^{3+} (aq) \]

**Final balanced reaction equation:**

*Provide the balanced equation here.*

---

**[3] Given the Standard Reduction Potentials at 25°C, Mn\(^{2+}\) + 2e\(^{-}\) → Mn E° = -1.185V and Hg\(^{2+}\) + 2e\(^{-}\) → Hg E° = +0.851V, what is the spontaneous reaction between these two half-cells and what is the potential of the cell?**

---

**[4] For the reaction:**

\[ \text{Sn} (s) + 2\text{Cu}^{2+} (aq) \rightarrow \text{Sn}^{2+} (aq) + 2\text{Cu}^{+} (aq) \]

The calculated E° = +0.291V, calculate ΔG° and K for this reaction. R = 8.314 J/mol·K.

---

**[5]** *(Work on the back)*

For the reaction:

\[ \text{Cu} (s) + 2\text{Ag}^{+} \rightarrow \text{Cu}^{2+} + 2\text{Ag} (s) \]

E° = +0.462 V. Calculate the potential of the following cell shown in cell notation. Is this non-standard cell spontaneous?

\[ \text{Cu}(s) | \text{Cu}^{2+} (0.0037M) || \text{Ag}^{+} (0.016M) | \text{Ag}(s) \]

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Transcribed Image Text:Certainly! Here's the transcription suitable for an educational website: --- **Balancing Redox Reactions and Calculating Cell Potentials** **[1] In basic solution, balance the redox reaction:** \[ \text{MnO}_4^{2-} (aq) \rightarrow \text{MnO}_4^{-} (aq) + \text{MnO}_2 (s) \] **Final balanced reaction equation:** *Provide the balanced equation here.* --- **[2] In acidic solution, balance the redox reaction:** \[ \text{Xe} (g) + \text{Cr}_2\text{O}_7^{2-} (aq) \rightarrow \text{XeO}_3 (s) + \text{Cr}^{3+} (aq) \] **Final balanced reaction equation:** *Provide the balanced equation here.* --- **[3] Given the Standard Reduction Potentials at 25°C, Mn\(^{2+}\) + 2e\(^{-}\) → Mn E° = -1.185V and Hg\(^{2+}\) + 2e\(^{-}\) → Hg E° = +0.851V, what is the spontaneous reaction between these two half-cells and what is the potential of the cell?** --- **[4] For the reaction:** \[ \text{Sn} (s) + 2\text{Cu}^{2+} (aq) \rightarrow \text{Sn}^{2+} (aq) + 2\text{Cu}^{+} (aq) \] The calculated E° = +0.291V, calculate ΔG° and K for this reaction. R = 8.314 J/mol·K. --- **[5]** *(Work on the back)* For the reaction: \[ \text{Cu} (s) + 2\text{Ag}^{+} \rightarrow \text{Cu}^{2+} + 2\text{Ag} (s) \] E° = +0.462 V. Calculate the potential of the following cell shown in cell notation. Is this non-standard cell spontaneous? \[ \text{Cu}(s) | \text{Cu}^{2+} (0.0037M) || \text{Ag}^{+} (0.016M) | \text{Ag}(s) \] ---
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