1- If z = 1+ y2, we can write: a) z = 1- (iy)?, b) z = 1- iy?, c) z = 1- iy, d) z 1 + (iy)? 2- If z, = 1+i and zz = i then 4 equal: a) 1 + 1, b) -1+ 1, c) -1 - i, d) 1 -i 3- If z = x+ iy, 2 = x- ly, then zz equal: a) Vx? + y?, b) x - y, c) x? + y*, d) x? + iy?
1- If z = 1+ y2, we can write: a) z = 1- (iy)?, b) z = 1- iy?, c) z = 1- iy, d) z 1 + (iy)? 2- If z, = 1+i and zz = i then 4 equal: a) 1 + 1, b) -1+ 1, c) -1 - i, d) 1 -i 3- If z = x+ iy, 2 = x- ly, then zz equal: a) Vx? + y?, b) x - y, c) x? + y*, d) x? + iy?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![1- If z = 1+ y2, we can write:
a) z = 1- (iy)?, b) z = 1- iy?, c) z = 1- iy, d) z = 1 + (iy)?
2- If z1 = 1+i and z2 = i* then equal:
b) -1+ i,
%3D
a) 1+i,
с) -1- і,
d) 1-i
3- If z = x + iy, z = x- iy, then zz equal:
a) Vr + y7, b) x² - y',
c) x? + y?,
d) x? + iy?
4- Im(iz) equal:
a) Re(z)
c) -Re(2)
b) Im(z)
d) -ilm(iz)
5- arg () equal :-
a) - arg(7),
b) arg (z),
c) arg (-7), d)-arg(z)
Q2) Find(1 + iv3 )(i + v3)
Q3| If a + ib
(ix+1)2
find a? + b?
x+1
Q4) By using polynomial equation, find (1 + i)? and (i + 1)3
Q5| Find the complex number z if arg(z – 1) = and arg(z) = *
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc43127c1-c664-49e0-8f99-fc239acb2e1e%2Fa5caf848-ce10-4a96-8071-3197523c7bb9%2Ff7uwmo9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1- If z = 1+ y2, we can write:
a) z = 1- (iy)?, b) z = 1- iy?, c) z = 1- iy, d) z = 1 + (iy)?
2- If z1 = 1+i and z2 = i* then equal:
b) -1+ i,
%3D
a) 1+i,
с) -1- і,
d) 1-i
3- If z = x + iy, z = x- iy, then zz equal:
a) Vr + y7, b) x² - y',
c) x? + y?,
d) x? + iy?
4- Im(iz) equal:
a) Re(z)
c) -Re(2)
b) Im(z)
d) -ilm(iz)
5- arg () equal :-
a) - arg(7),
b) arg (z),
c) arg (-7), d)-arg(z)
Q2) Find(1 + iv3 )(i + v3)
Q3| If a + ib
(ix+1)2
find a? + b?
x+1
Q4) By using polynomial equation, find (1 + i)? and (i + 1)3
Q5| Find the complex number z if arg(z – 1) = and arg(z) = *
%3D
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