QI) Choose Correct answer? write number of question and (leter of choice) 1- If x = a:e:b, then, the x-axis of plot(x) will be: b-) a:e:b. a-) 1: length(x). c-) a:b. d-) no one from these 2- ezplot('x+3') shows: a-)Graph of line at (0,2pi). e-)graph of x+3=0 at (-2*pi 2"pi). b-) gives error becuase x is unknown. d-) no one from these 3- for two polynomials p and g will have: a-) p*g conv(p,g) and g/p invconv(g.p). b-) conv(p,g) = p*g and deconv(p.g) = p/g. c-) vector p- vector g. gives plolynomial p - polynomial g. d-) if the length of both vectors are not same we can't add them.
Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
![QI) Choose Correct answer? write number of question and (leter of choice)
1- If x = a:e:b, then, the x-axis of plot(x) will be:
b-) a:c:b.
a-) 1: length(x).
c-) a:b.
d-) no one from these
2- czplot('x+3') shows:
a-)Graph of line at (0,2pi).
e-)graph of x+3=0 at (-2*pi 2*pi).
b-) gives error becuase x is unknown.
d-) no one from these
3- for two polynomials p and g will have:
a-) p*g = conv(p,g) and g/p invconv(g.p).
b-) conv(p,g) = p*g and deconv(p.g) = p/g.
c-) vector p- vector g. gives plolynomial p - polynomial g.
d-) if the length of both vectors are not same we can't add them.
4- length of X-sum(repmat(rand(2,3),2,3)), equal:
a-)length(X)=6. b-) length(X)=4. c-)length(X)=9. d-)length(X)=3.
5. A=rand(3,4); >> A(4,5)=1, this means A(4,:) and last column in A:
a-)have ony one zero;
c-)have the same lemgths
b-) All eaements will be zero
d-)sum (A(:,5)=1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F162fe9ab-79d2-44ea-80f0-0fb1457fe461%2Faef32af9-3255-445c-95cb-d7bb338d3ccc%2F8pju2o9_processed.jpeg&w=3840&q=75)
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