1) If the electrical power lines in a certain neighborhood deliver electricity at 72,000 volts, which combination of the following transformer coil pairs will supply electricity at 120V to customer's homes? (Primary coil first, secondary into homes second.) A) 15,000 :: 25 B) 25 :: 15,000 C) 600 :: 120 D) 120 :: 600 E) 15,000 :: 120
1) If the electrical power lines in a certain neighborhood deliver electricity at 72,000 volts, which combination of the following transformer coil pairs will supply electricity at 120V to customer's homes? (Primary coil first, secondary into homes second.) A) 15,000 :: 25 B) 25 :: 15,000 C) 600 :: 120 D) 120 :: 600 E) 15,000 :: 120
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![### Transformer Coil Pairs for Supplying Electricity
**Question 1:**
If the electrical power lines in a certain neighborhood deliver electricity at 72,000 volts, which combination of the following transformer coil pairs will supply electricity at 120V to customers' homes? (Primary coil first, secondary into homes second.)
**Options:**
A) 15,000 :: 25
B) 25 :: 15,000
C) 600 :: 120
D) 120 :: 600
E) 15,000 :: 120
---
### Explanation:
To solve this problem, we need to determine which pair of transformer coils can step down the voltage from 72,000 volts to 120 volts as required for the household electricity supply.
#### Basic Transformer Formula:
\[ \frac{V_p}{V_s} = \frac{N_p}{N_s} \]
Where:
- \( V_p \) = Primary voltage
- \( V_s \) = Secondary voltage
- \( N_p \) = Number of turns in the primary coil
- \( N_s \) = Number of turns in the secondary coil
For the given problem:
- \( V_p = 72,000 \) volts
- \( V_s = 120 \) volts
Let's analyze each option:
**Option A)** 15,000 :: 25
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{15,000}{25} = 600 \]
This pair works because \( \frac{N_p}{N_s} = 600 \).
**Option B)** 25 :: 15,000
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{25}{15,000} = 0.00166 \]
This pair does not work because the ratio is not 600.
**Option C)** 600 :: 120
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{600}{120} = 5 \]
This pair does not work because the ratio is not 600.
**Option D)** 120 :: 600
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{120}{600} = 0.2 \]
This pair does not work because the ratio is not 600.
**Option E)** 15,000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5aab90fe-f662-4329-be2f-bc153bcfca52%2F0523540a-f86d-496a-bab6-2e365a68ff38%2Fso7rjry_processed.png&w=3840&q=75)
Transcribed Image Text:### Transformer Coil Pairs for Supplying Electricity
**Question 1:**
If the electrical power lines in a certain neighborhood deliver electricity at 72,000 volts, which combination of the following transformer coil pairs will supply electricity at 120V to customers' homes? (Primary coil first, secondary into homes second.)
**Options:**
A) 15,000 :: 25
B) 25 :: 15,000
C) 600 :: 120
D) 120 :: 600
E) 15,000 :: 120
---
### Explanation:
To solve this problem, we need to determine which pair of transformer coils can step down the voltage from 72,000 volts to 120 volts as required for the household electricity supply.
#### Basic Transformer Formula:
\[ \frac{V_p}{V_s} = \frac{N_p}{N_s} \]
Where:
- \( V_p \) = Primary voltage
- \( V_s \) = Secondary voltage
- \( N_p \) = Number of turns in the primary coil
- \( N_s \) = Number of turns in the secondary coil
For the given problem:
- \( V_p = 72,000 \) volts
- \( V_s = 120 \) volts
Let's analyze each option:
**Option A)** 15,000 :: 25
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{15,000}{25} = 600 \]
This pair works because \( \frac{N_p}{N_s} = 600 \).
**Option B)** 25 :: 15,000
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{25}{15,000} = 0.00166 \]
This pair does not work because the ratio is not 600.
**Option C)** 600 :: 120
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{600}{120} = 5 \]
This pair does not work because the ratio is not 600.
**Option D)** 120 :: 600
\[ \frac{72,000}{120} = 600 \Rightarrow \frac{120}{600} = 0.2 \]
This pair does not work because the ratio is not 600.
**Option E)** 15,000
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