1 == - (1—x?)2 dx I = Sdx(1-х2)23

Name: 1 == - (1—x?)2 dx I = Sdx(1-х2)23
Uploaded: 2024-03-20T06:46:42.000Z
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Description: 1 == - (1—x?)2 dx I = Sdx(1-х2)23

It is known that: 1-cos2x=sin2x∫sec2x=tan x+Ctansin-1x=x1-x212

Answered: 1 I = J dx (1-x²)Z %3D 3

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section1.2: Exponents And Radicals

Problem 35E

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