1 HW: K,Cr,0, + HCl → KCl + CrClz + H20 + Cl2

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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be immersed and cell of the follow type is produced:
Ag|AGCLHC(aq)\glass|unknownsolution|KCl|Hg,Cl,
(s)
Balancing Oxidation-Reduction Equations:
Ex: HNO3 + H2S → NO +S + H20
Sol:
3e- +N+5 → N+2]×2= 6e- + 2N*5
S-2 S° + 2e-]x3 = 3S-2 3S° + 6e-
Reduction
Oxidation
- 2N+2
8H260
2HNO, +3H,S → 2NO + 3S + 4H,0 81, 60
2N+5 + 3S-2 –→
2N+2 + 35°
+6
Ex: KMN0, + KCl + H,šö,
Sol: + +X-8-o
- MNSO, + K,S0, + H¿0 + Cl,
X+6-8=0
X= +2
10e- + 2Mn+7 –
2Mn+2 Red
Asid
5e-+ Mn+7 – Mn+2 =
201- Cl2 + 2e¯ = 10Cl- 5Cl, + 10e-
2KMN0, + 10KCI + 8H2S0, → 2MNSO, + 5C12 + 8H20
+7
25
2 Mn+ 10 c1
> 2 Mn?
2K Mn nkcl
2 .Sa I Mnsout 5cl2+
Solve the question with such
steps
Thanks
Transcribed Image Text:be immersed and cell of the follow type is produced: Ag|AGCLHC(aq)\glass|unknownsolution|KCl|Hg,Cl, (s) Balancing Oxidation-Reduction Equations: Ex: HNO3 + H2S → NO +S + H20 Sol: 3e- +N+5 → N+2]×2= 6e- + 2N*5 S-2 S° + 2e-]x3 = 3S-2 3S° + 6e- Reduction Oxidation - 2N+2 8H260 2HNO, +3H,S → 2NO + 3S + 4H,0 81, 60 2N+5 + 3S-2 –→ 2N+2 + 35° +6 Ex: KMN0, + KCl + H,šö, Sol: + +X-8-o - MNSO, + K,S0, + H¿0 + Cl, X+6-8=0 X= +2 10e- + 2Mn+7 – 2Mn+2 Red Asid 5e-+ Mn+7 – Mn+2 = 201- Cl2 + 2e¯ = 10Cl- 5Cl, + 10e- 2KMN0, + 10KCI + 8H2S0, → 2MNSO, + 5C12 + 8H20 +7 25 2 Mn+ 10 c1 > 2 Mn? 2K Mn nkcl 2 .Sa I Mnsout 5cl2+ Solve the question with such steps Thanks
Balancing osidation-reduction
Equationa
1 HW: K Cr0,+ HCL
2 HW:Zn + NaNO, + NaOH → NazZn02 + NH3 + H2O
KCI + CrCl, + H20 + Cl2
Transcribed Image Text:Balancing osidation-reduction Equationa 1 HW: K Cr0,+ HCL 2 HW:Zn + NaNO, + NaOH → NazZn02 + NH3 + H2O KCI + CrCl, + H20 + Cl2
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