(1) H3C-CH3 + F H3C-CH2 + H-F (2) H3C-CH, F-F H3C-CH,F F

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Would the net reaction be exothermic? Please use BDE to show calculations for determining delta H
### Chemical Reactions Involving Free Radicals

**Reaction 1:**
\[ \text{(1)} \quad \text{H}_3\text{C} - \text{CH}_3 + \text{F} \cdot \rightarrow \text{H}_3\text{C} - \text{CH}_2 \cdot + \text{H} - \text{F} \]

- **Reactants:** Ethane (\(\text{H}_3\text{C} - \text{CH}_3\)) and a fluorine radical (\(\text{F} \cdot \)).
- **Products:** Ethyl radical (\(\text{H}_3\text{C} - \text{CH}_2 \cdot\)) and hydrogen fluoride (\(\text{H} - \text{F}\)).

**Reaction 2:**
\[ \text{(2)} \quad \text{H}_3\text{C} - \text{CH}_2 \cdot + \text{F} - \text{F} \rightarrow \text{H}_3\text{C} - \text{CH}_2\text{F} + \text{F} \cdot \]

- **Reactants:** Ethyl radical (\(\text{H}_3\text{C} - \text{CH}_2 \cdot\)) and molecular fluorine (\(\text{F} - \text{F}\)).
- **Products:** Fluoroethane (\(\text{H}_3\text{C} - \text{CH}_2\text{F}\)) and a fluorine radical (\(\text{F} \cdot\)).

### Explanation

These reactions illustrate the steps involved in the halogenation of alkanes through a free radical mechanism. The first reaction involves the abstraction of a hydrogen atom by a fluorine radical from ethane, forming an ethyl radical and hydrogen fluoride. The second reaction shows the ethyl radical reacting with molecular fluorine to form fluoroethane and regenerate a fluorine radical. This regeneration of the radical signifies a chain reaction typical of radical halogenation.
Transcribed Image Text:### Chemical Reactions Involving Free Radicals **Reaction 1:** \[ \text{(1)} \quad \text{H}_3\text{C} - \text{CH}_3 + \text{F} \cdot \rightarrow \text{H}_3\text{C} - \text{CH}_2 \cdot + \text{H} - \text{F} \] - **Reactants:** Ethane (\(\text{H}_3\text{C} - \text{CH}_3\)) and a fluorine radical (\(\text{F} \cdot \)). - **Products:** Ethyl radical (\(\text{H}_3\text{C} - \text{CH}_2 \cdot\)) and hydrogen fluoride (\(\text{H} - \text{F}\)). **Reaction 2:** \[ \text{(2)} \quad \text{H}_3\text{C} - \text{CH}_2 \cdot + \text{F} - \text{F} \rightarrow \text{H}_3\text{C} - \text{CH}_2\text{F} + \text{F} \cdot \] - **Reactants:** Ethyl radical (\(\text{H}_3\text{C} - \text{CH}_2 \cdot\)) and molecular fluorine (\(\text{F} - \text{F}\)). - **Products:** Fluoroethane (\(\text{H}_3\text{C} - \text{CH}_2\text{F}\)) and a fluorine radical (\(\text{F} \cdot\)). ### Explanation These reactions illustrate the steps involved in the halogenation of alkanes through a free radical mechanism. The first reaction involves the abstraction of a hydrogen atom by a fluorine radical from ethane, forming an ethyl radical and hydrogen fluoride. The second reaction shows the ethyl radical reacting with molecular fluorine to form fluoroethane and regenerate a fluorine radical. This regeneration of the radical signifies a chain reaction typical of radical halogenation.
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