AcidsWhat Is ne PHO d) Titration of a weak diprotic acid.1- H2SO4 is a strong acid in its first ionization; but a weak acid in its secondionization with Ka = 0.012. Calculate the pH of a 0.056 M solution of H2SO4.0.0120.08190.056O 1.0862- Calculate the hydronium ion concentration and the pH of a 10-2 M NaH2Asolution. Given: The dissociation constants of H2A are Ka1 = 10-2 and Ka2 = 10-7%3D%3D O 0.056O 1.0862- Calculate the hydronium ion concentration and the pH of a 10-2 M NaH2Asolution. Given: The dissociation constants of H2A are Ka1 = 10-2 and Ka2 = 10-7.O 4.5Dohat is the dominant form of aspartic acid (a triprotic acid (H3A+)) at a pH of

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Answered: 1- H2SO4 is a strong acid in its first…

1- H2SO4 is a strong acid in its first ionization; but a weak acid in its second ionization with Ka = 0.012. Calculate the pH of a 0.056 M solution of H2SO4. O 0.012 0.0819 0.056

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Ionic Equilibrium

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Arrhenius Acid

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Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Question

Acids
What Is ne PH
O d) Titration of a weak diprotic acid.
1- H2SO4 is a strong acid in its first ionization; but a weak acid in its second
ionization with Ka = 0.012. Calculate the pH of a 0.056 M solution of H2SO4.
0.012
0.0819
0.056
O 1.086
2- Calculate the hydronium ion concentration and the pH of a 10-2 M NaH2A
solution. Given: The dissociation constants of H2A are Ka1 = 10-2 and Ka2 = 10-7
%3D
%3D

O 0.056
O 1.086
2- Calculate the hydronium ion concentration and the pH of a 10-2 M NaH2A
solution. Given: The dissociation constants of H2A are Ka1 = 10-2 and Ka2 = 10-7.
O 4.5
Dohat is the dominant form of aspartic acid (a triprotic acid (H3A+)) at a pH of

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Conjugate acid of any base is defined as the species formed when the base accepts a proton. And the conjugate base of any acid is defined as the species formed when the base donates a proton. Hence in the conjugate acid-base pair, there will be a difference of 1 proton only. In the above reaction, the base NH3 is accepting a proton from the acid HF to form + NH4* ions. Hence NH3/NH4* is a conjugate acid-base pair. And the acid HF is donating a proton to form the conjugate base F. Hence HF/F is a conjugate acid-base pair. Hence the answer is NH3/NH4* & HF/F". ANSWER IN NO. 4
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