1) f(x) = -(x– 3)² + 3DomainRangeZerosx-intercepty-interceptContinuityIncrease IntervalDecrease Interval2-1MaximumMinimumx = -2, find f(x)x = 6, find f(x)-1--2as x -o0as x + +00Vertical AsymptoteHorizontal Asymptote2) f(x) = 3(-x + 1)³ + 2DomainRangeZerosx-intercepty-interceptContinuityIncrease IntervalDecrease Interval21-MaximumMinimumx = -2, find f(x)x = 3, find f(x)-2-1-1-210Vertical AsymptoteHorizontal Asymptote-3as x -00as x +0022T To DoA Notifications107W InboxCalendar

For x-intercept , y=0 For y-intercept , x=0. Horizontal Asymptote : The line y=L is a horizontal…

Answered: 1) f(x) = -(x- 3)² + 3 Domain Range…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter4: Polynomial And Rational Functions

Section: Chapter Questions

Problem 15T

See similar textbooks

Similar questions

What is the purpose of the Intermediate Value Theorem?
Please
Asap
Зх-4 (5) Let f(x) ', x E [-2,2], find the absolute maximum and minimum x2+1 values of f(x).
Let f (x) = a +x² 3x - Ca) Determine the y intercept of f(x) and any symmetry. (Don't ind the x-intercepts.) (b) Use the first derivative to determine the relative maximums minimums and intervals of increase/decrease of f(x). You do not need to submit a sign chart or other work. (c) Use the second derivative to determine the points of inflection and intervals of concavity of f(x). You do not need to submit a sign chart or other work.
let f(x)= X4+1 a find f'() + simplity
Prob. 6 (a) (10 point) Let f(x) = 2x² – 3. Find ƒ'(−2) using only the limit definition of derivatives. (b) (10 p.) If ƒ(x) = √√x + 6, find the derivative f'(c) at an arbitrary point c using only the limit definition of derivatives.
Differentiate the following function. y=x(x³ +5) ³ Choose the correct setup below to differentiate the function. [x(x5 +5)³] = (x)•. J :(x5 + 5)³) + ((x³ +5)³).) dx d « (x5 + 5)³] = « - -(x* + 5) ³) - ((x³ +5)³).) dx dx [x (x* +5)³]=2• [x(x° +5) ³].[x (x* + 5) ³] dx dx d d Ix(x5 +5)³]= x) • 3 (a5 +5) + ((x³ +5) ³) · x) d [x (x5 + 5)³] = (x) • ) + ( (x5 + 5) ³) • -c() + ( (x5 +5) ³) • (x5 + 5) ³) dx dx dx d [x(x* + 5)³ : dx
Find value a such that f(x)={x^2+2x-1 if x not equal to 1 a if x=1 is contiuous at x=1
Find max and min of function on the interval f(x)=-x4-x3+5x2-4 on [-2,1]
Find the area between the curve y = x² + 12x + 27 and the x-axis from x = -3 to x = -1. Step 1 Notice that the curve is a parabola with x-intercepts (-3 -3 ,0) and (-9, 0). Within our interval [-3, -1], f(x) is nonnegative nonnegative Step 2 Therefore, our function is continuous and f(x) 2 0 on [a, b], and we can use the definite interval as follows to measure the area under the curve. If fis a continuous function on [a, b] and f(x) > 0 on [a, b], then the exact area between y = f(x) and the x-axis from x = a to x = b is given by Area = rw) dx. 9. Therefore, set up the definite integral for our function. + 12x + 27 1 + 12r + 27 dx Step 3 Now we use the Fundamental Theorem of Calculus to evaluate the integral. First integrate and write the 9. answer in the form (x) dx = F(x)", where F'(x) = f(x). | (x²+ 12x + 27) dx = -3 -3

Recommended textbooks for you

Algebra & Trigonometry with Analytic Geometry

Algebra

ISBN:

9781133382119

Author:

Swokowski

Publisher:

Cengage

College Algebra (MindTap Course List)

Algebra

ISBN:

9781305652231

Author:

R. David Gustafson, Jeff Hughes

Publisher:

Cengage Learning

Algebra & Trigonometry with Analytic Geometry

Algebra

ISBN:

9781133382119

Author:

Swokowski

Publisher:

Cengage

College Algebra (MindTap Course List)

Algebra

ISBN:

9781305652231

Author:

R. David Gustafson, Jeff Hughes

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS

1) f(x) = -(x- 3)² + 3 Domain Range Zeros x-intercept y-intercept Continuity Increase Interval Decrease Interval -1 Maximum Minimum x=-2, find f(x) x= 6, find f(x) -2 as x -0o as x +00 Vertical Asymptote Horizontal Asymptote