(1) For t < 2 s, the switch is closed, and you may assume the system has reached steady state. The switch opens at time t = 2 s. (a) Find i (2 s). (b) Find ia(t) for t > 2 s. Write the equation. 6 A 202 202 ia(t) ΖΩ 12 μΗ ia (2-s)
(1) For t < 2 s, the switch is closed, and you may assume the system has reached steady state. The switch opens at time t = 2 s. (a) Find i (2 s). (b) Find ia(t) for t > 2 s. Write the equation. 6 A 202 202 ia(t) ΖΩ 12 μΗ ia (2-s)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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
Transcribed Image Text:### Electrical Circuit Analysis
**Problem Statement:**
For \( t < 2 \, \text{s} \), the switch is closed, and you may assume the system has reached a steady state. The switch opens at time \( t = 2 \, \text{s} \).
**Tasks:**
(a) Find \( i_a(2^- \, \text{s}) \).
(b) Find \( i_a(t) \) for \( t > 2 \, \text{s} \). Write the equation.
**Circuit Diagram:**
- A current source of \( 6 \, \text{A} \).
- Two resistors in parallel, each of \( 2 \, \Omega \).
- A series circuit with a \( 2 \, \Omega \) resistor, an inductor of \( 12 \, \mu\text{H} \), and the switch.
- The current \( i_a \) flows through the second \( 2 \, \Omega \) resistor and the inductor after the switch is opened.
**Analysis Explanation:**
1. **Steady State Analysis (Before \( t = 2 \, \text{s} \)):**
- Determine the behavior of the circuit when the switch is closed and the system is in steady state.
- Calculate the initial current \( i_a(2^- \, \text{s})\) before the switch opens.
2. **Transient Analysis (After \( t = 2 \, \text{s} \)):**
- Analyze the circuit when the switch is opened and the behavior of the inductor becomes significant.
- Write down the equation for \( i_a(t) \) for \( t > 2 \, \text{s} \).
This analysis involves calculating the current \( i_a \) at both before and after the switch is opened. The equations will describe how the circuit responds due to the inductance when the switch opens.
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