(1) For a lens with focal length f, find the smallest distance possible between the object and its real image. (2) Graph the distance between the object and the real image as a function of the distance of the object from the lens. Does your graph agree with the result you found in part (a)?
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(1) For a lens with focal length f, find the smallest distance possible between the object and its real image. (2) Graph the distance between the object and the real image as a function of the distance of the object from the lens. Does your graph agree with the result you found in part (a)?
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- Two thin lenses with focal lengths of magnitude 15.0 cm, the first diverging and the second converging, are placed 12.00 cm apart. An object 3.00 mm tall is placed 5.50 cm to the left of the first (diverging) lens. Where is the image formed by the first lens located? Please provide a detailed explanation of the process. How far from the object is the final image formed? Please describe the steps taken to reach to your conclusion.Shown in the figure below is a system containing two lenses and an object. The focal lengths of the two lenses are f1 = -19 cm and f2 = 9.5 cm. The two lengths indicated in the figure are L1 = 28.5 cm and L2 = 15.2 cm. Determine all the following about the image from the first lens only:Object distance for the first lens, d01. cmImage distance for the first lens, di1. cmMagnification of the first lens, m1. The second lens uses the image from the first lens as its object. Determine all the following about the image from the second lens:Object distance for the second lens, d01. cmImage distance for the second lens, di1. cmMagnification of the second lens, m1. Determine the magnification of the whole system, mtot. Select the correct attributes of the final image of the system: virtual real enlarged shrunk upside down right side up(Dove Prism) A new type of prism inverts an image that comes in through one end (see Figure 1). The prism will be shaped like a trapezoid with a square cross-section and sides cut at a 45° angle, and that the prism will be made of a plastic called BK7 that has an index of refraction of 1.517. Decide on the dimensions of the prism in order to maximize the size of the image that can be inverted (see incoming/outgoing rays in the side view in Figure 2). How long (length B in Figure 1) should the prism be in terms of its height (length A in Figure 1)? What happens to an image that enters the prism on one side of its long face (see figure 3)? Make a drawing tracing the path of rays 4, 5, and 6 in figure 3 to find out. Figure 1 Figure 2 1 3 2 45° 3 1 Figure 2 Figure 3 45° Figure 3 4 5 6
- An object is 12.0 cm from a converging lens (focal length = 15.0 cm). Determine the image magnification. Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the magnification is significant.A converging lens has a focal length of 4.0 cm A 1.5 cm object is placed 6.0 cm to the left of the lens (as shown in the diagram below) Part A The distance of the image will be ανα ΑΣφ d; = cm Submit Request Answer Part B The height of the image will be Πνη ΑΣφ ? h4 = cm Submit Request Answer Part C The image is and O real, upright O real, inverted O virtual, inverted O virtual, uprightHow could you very quickly make an approximate measurement of the focal length of a converging lens? Could the same method be applied if you wished to use a diverging lens? Explain.
- Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. (a) (b) (c) (d) (e) Lens i m R/V I/NI Side +14 C, 24 (a) Number Units (b) Number i Units (c) (d) (e) > >Spherical refracting surfaces. An object O stands on the central axis of a spherical refracting surface. For this situation (see the table below, all distances are in centimeters), nį is the index of refraction where the object is located, n2 is the index of refraction on the other side of the refracting surface. Find (a) the image distance i, and determine whether the image is (b) real or virtual and (c) on the same side of the surface as object O or on the opposite side. (a) (b) (c) n1 n2 p ri R/V Side 1.5 1.3 +70 +56 (a) Number i Units (b) (c) > >A 4 cm tall light bulb is placed a distance of 35.5 cm from a diverging lens whose focal length magnitude is 12.2 cm. Determine the image distance from the lens, the image height, and the magnification. Put into words what your calculations physically represent about the image.