Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![### Geometry Problem: Finding the Value of x
**1) Find the value of x.**
#### Diagram:
- The diagram shows a circle with two line segments intersecting inside the circle.
- One of the angles formed by the intersecting lines inside the circle is labeled as \( x^\circ \).
- One of the angles on the left side of the circle is labeled as \( 40^\circ \).
- Another angle on the right side of the circle is labeled as \( 96^\circ \).
To solve the problem, remember that the angle \( x^\circ \) inside the circle, formed by the intersecting lines, is related to the external angles \( 40^\circ \) and \( 96^\circ \). The formula we use for such situations is:
\[ x = \frac{1}{2} \times (\text{angle1} + \text{angle2}) \]
Substitute the given angles:
\[ x = \frac{1}{2} \times (40^\circ + 96^\circ) \]
Now, calculate:
\[ x = \frac{1}{2} \times 136^\circ \]
\[ x = 68^\circ \]
Therefore, the value of \( x \) is \( 68^\circ \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba437994-7eb2-41d2-bf90-86c7e632409d%2F4cba026f-2db1-4c3d-a99e-99b56cdcdb7b%2Fyqv32ka_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Geometry Problem: Finding the Value of x
**1) Find the value of x.**
#### Diagram:
- The diagram shows a circle with two line segments intersecting inside the circle.
- One of the angles formed by the intersecting lines inside the circle is labeled as \( x^\circ \).
- One of the angles on the left side of the circle is labeled as \( 40^\circ \).
- Another angle on the right side of the circle is labeled as \( 96^\circ \).
To solve the problem, remember that the angle \( x^\circ \) inside the circle, formed by the intersecting lines, is related to the external angles \( 40^\circ \) and \( 96^\circ \). The formula we use for such situations is:
\[ x = \frac{1}{2} \times (\text{angle1} + \text{angle2}) \]
Substitute the given angles:
\[ x = \frac{1}{2} \times (40^\circ + 96^\circ) \]
Now, calculate:
\[ x = \frac{1}{2} \times 136^\circ \]
\[ x = 68^\circ \]
Therefore, the value of \( x \) is \( 68^\circ \).
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