Please see attached questions 1) Find' the inverse Laplace transform of2s+5a) 5s+6b)3s+552+4s+13(s+1)²c) -s-62) For the circuit shown in Fig. 1, the switch is closed for a long time prior to t = 0, For theparameters R = 10 kN; Ra = 15 KN; C = 10 F and V = 25 V, find expression for re(t) nnclsketch it to scale for -60

Solution 1.(a)Taking inverse laplace transform =L-12s+5s2+5s+6 =L-12s+5(s+3)(s+2)…

Answered: 1) Find' the inverse Laplace transform…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Please see attached questions

1) Find' the inverse Laplace transform of
2s+5
a) 5s+6
b)
3s+5
52+4s+13
(s+1)²
c) -s-6
2) For the circuit shown in Fig. 1, the switch is closed for a long time prior to t = 0, For the
parameters R = 10 kN; Ra = 15 KN; C = 10 F and V = 25 V, find expression for re(t) nncl
sketch it to scale for -60<ts 300 ms.
t-0
R
R2
Figure 1: Problem 2

Expert Solution

Step 1

$S o l u t i o n 1 . (a) T a k i n g i n v e r s e l a p l a c e t r a n s f o r m = L^{- 1} \{\frac{2 s + 5}{s^{2} + 5 s + 6}\} = L^{- 1} \{\frac{2 s + 5}{(s + 3) (s + 2)}\} = L^{- 1} \{\frac{2 (s + 2) + 1}{(s + 3) (s + 2)}\} = L^{- 1} \{\frac{2 (s + 2)}{(s + 3) (s + 2)}\} + L^{- 1} \{\frac{1}{(s + 3) (s + 2)}\} = L^{- 1} \{\frac{2}{(s + 3)}\} + L^{- 1} \{\frac{1}{s + 2} - \frac{1}{s + 3}\} = 2 L^{- 1} \{\frac{1}{(s + 3)}\} + L^{- 1} \{\frac{1}{(s + 2)}\} - L^{- 1} \{\frac{1}{(s + 3)}\} = L^{- 1} \{\frac{1}{(s + 3)}\} + L^{- 1} \{\frac{1}{(s + 2)}\} = e^{- 3 t} + e^{- 2 t}$

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