1 Find the area between the graph of x = y² and the y-axis on the interval [1,4]. -0.5 4 3 2- 1 0 Y 0.5 1 1.5

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the area between the graph of \( x = \frac{1}{y^2} \) and the y-axis on the interval \([1, 4]\).

**Graph Description:**

The graph provided shows a curve representing the function \( x = \frac{1}{y^2} \). It is a downward-sloping curve starting from \( y = 1 \) to \( y = 4 \). The area between this curve and the y-axis is shaded, indicating the region for which the area needs to be calculated. The x-axis range is from \(-0.5\) to \(1.5\), while the y-axis range is from \(0\) to \(4\).

**Solution Approach:**

To find the area, set up the integral of the function \( x = \frac{1}{y^2} \) with respect to \( y \) from \( y = 1 \) to \( y = 4 \).

\[ 
\text{Area} = \int_{1}^{4} \frac{1}{y^2} \, dy 
\]
Transcribed Image Text:**Problem Statement:** Find the area between the graph of \( x = \frac{1}{y^2} \) and the y-axis on the interval \([1, 4]\). **Graph Description:** The graph provided shows a curve representing the function \( x = \frac{1}{y^2} \). It is a downward-sloping curve starting from \( y = 1 \) to \( y = 4 \). The area between this curve and the y-axis is shaded, indicating the region for which the area needs to be calculated. The x-axis range is from \(-0.5\) to \(1.5\), while the y-axis range is from \(0\) to \(4\). **Solution Approach:** To find the area, set up the integral of the function \( x = \frac{1}{y^2} \) with respect to \( y \) from \( y = 1 \) to \( y = 4 \). \[ \text{Area} = \int_{1}^{4} \frac{1}{y^2} \, dy \]
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to find the area between the curve x=1/y^2 and y axis in tge interval [1,4]

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