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(1) Design the circuit to reduce the input voltage by 40%, by using the circuit connected through an ideal Operational Amplifier. (You are free to choose any electric element)

(1) Design the circuit to reduce the input voltage by 40%, by using the circuit connected through an ideal Operational Amplifier. (You are free to choose any electric element)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The complete response is the sum of the natural response and the forced response X = Xn+Xf Natural response of a first-order circuit Natural response of a second-order circuit CASE Overdamped Critically damped Underdamped az S1 = FORCING FUNCTION K Kt K₁² K sin cot Ke at Forced response of a first-order, or a second-order circuit + A₁ NATURAL FREQUENCIES $1,52 = -α± √√² - 0² $1,$₂=-α S1, S2 = -x±j√√/0²-a² -α±jood dx dt d²x dt² Solution of the Second-Order Differential Equation d²x x(t) = xn(t) + xf (t) a2 dt² + a。x = f(t) + A1 dx dt "xn(t)" = Aest Xn(t) = Ke-t/t + a。x = 0 -a₁ + √²-4a₂a0 242 - Xn(t) = A₁e³₁ª + A₂e³₂t ASSUMED RESPONSE A At + B At² +Bt+C A sin cot + B cos cot Ae-at NATURAL RESPONSE, Xn Ale+Azer (A₁+A₂t)e-at (A, cos coat+A₂ sin coat)e xn(t) = ? (a₂s² + a₁s+ao) = 0 -α₁ - √²-4a₂a0 242 NATURAL RESPONSE, Xn A₁ est + A₂e21 -α1 (A₁+A₂t)e (A₁ cos wat+A₂ sin wat)ext
Transcribed Image Text:The complete response is the sum of the natural response and the forced response X = Xn+Xf Natural response of a first-order circuit Natural response of a second-order circuit CASE Overdamped Critically damped Underdamped az S1 = FORCING FUNCTION K Kt K₁² K sin cot Ke at Forced response of a first-order, or a second-order circuit + A₁ NATURAL FREQUENCIES $1,52 = -α± √√² - 0² $1,$₂=-α S1, S2 = -x±j√√/0²-a² -α±jood dx dt d²x dt² Solution of the Second-Order Differential Equation d²x x(t) = xn(t) + xf (t) a2 dt² + a。x = f(t) + A1 dx dt "xn(t)" = Aest Xn(t) = Ke-t/t + a。x = 0 -a₁ + √²-4a₂a0 242 - Xn(t) = A₁e³₁ª + A₂e³₂t ASSUMED RESPONSE A At + B At² +Bt+C A sin cot + B cos cot Ae-at NATURAL RESPONSE, Xn Ale+Azer (A₁+A₂t)e-at (A, cos coat+A₂ sin coat)e xn(t) = ? (a₂s² + a₁s+ao) = 0 -α₁ - √²-4a₂a0 242 NATURAL RESPONSE, Xn A₁ est + A₂e21 -α1 (A₁+A₂t)e (A₁ cos wat+A₂ sin wat)ext
• Problem 1. Please answer the following questions, as directed in the questions. (1) Design the circuit to reduce the input voltage by 40%, by using the circuit connected through an ideal Operational Amplifier. (You are free to choose any electric element) (2) By using the models of the ideal Operational amplifier, Design the linear algebraic circuit as shown below. 1 3Y ■ Consider Z as Vout and x, y as Vin 1, Vin 2 (You are3 free to choose any electric element, but it should also include the operational amplifier) www R₁ T Vin m R₁ Brief catalog of the Operational Amplifier circuits (Based on the ideal operational amplifier) (a) Inverting amplifier U10-M R₁ U₂0-M R₂ Unw R₁ R₁ Ovout= R₁ Vout=- www R₁ - Vout R₁ R₁ R₁ R₁1+ R₂₂+. Rn Z = -2x + Vin (d) Summing amplifier Vin - R₁ R₁ 3 R₁ Vout + Vin (b) Noninverting amplifier R/K₁ R₂/K₂ 010- U20-W RJK3 V30-W R₂/(1-(K₁ + K₂ + K3)) www Vin (c) Voltage follower (buffer amplifier) R(K4-1) -Ovout Vin Ovout= K4(K₁v1 + K₂V2 + K303) (e) Noninverting summing amplifier
Transcribed Image Text:• Problem 1. Please answer the following questions, as directed in the questions. (1) Design the circuit to reduce the input voltage by 40%, by using the circuit connected through an ideal Operational Amplifier. (You are free to choose any electric element) (2) By using the models of the ideal Operational amplifier, Design the linear algebraic circuit as shown below. 1 3Y ■ Consider Z as Vout and x, y as Vin 1, Vin 2 (You are3 free to choose any electric element, but it should also include the operational amplifier) www R₁ T Vin m R₁ Brief catalog of the Operational Amplifier circuits (Based on the ideal operational amplifier) (a) Inverting amplifier U10-M R₁ U₂0-M R₂ Unw R₁ R₁ Ovout= R₁ Vout=- www R₁ - Vout R₁ R₁ R₁ R₁1+ R₂₂+. Rn Z = -2x + Vin (d) Summing amplifier Vin - R₁ R₁ 3 R₁ Vout + Vin (b) Noninverting amplifier R/K₁ R₂/K₂ 010- U20-W RJK3 V30-W R₂/(1-(K₁ + K₂ + K3)) www Vin (c) Voltage follower (buffer amplifier) R(K4-1) -Ovout Vin Ovout= K4(K₁v1 + K₂V2 + K303) (e) Noninverting summing amplifier
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